C语言 你如何在C中将void指针转换为char指针
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How do you convert void pointer to char pointer in C
提问by Jimmy
Ok this has been become sooo confusing to me. I just don't know what is wrong with this assignment:
好吧，这让我很困惑。我只是不知道这个任务有什么问题：
void *pa; void *pb;
char *ptemp; char *ptemp2;
ptemp = (char *)pa;
ptemp2 = (char *)pb;
Can anyone tell me why I'm getting this error:
谁能告诉我为什么会出现此错误：
error: invalid conversion from ‘void*' to ‘char*'
错误：从“void*”到“char*”的无效转换
回答by Armen Tsirunyan
Actually, there must be something wrong with your compiler(or you haven't told the full story). It is perfectly legal to cast a void*to char*. Furthermore, the conversion is implicitin C (unlike C++), that is, the following should compile as well
实际上，您的编译器一定有问题（或者您还没有讲述完整的故事）。这是完全合法的投出void*到char*。此外，转换在 C 中是隐式的（与 C++ 不同），也就是说，以下内容也应该编译
char* pChar;
void* pVoid;
pChar = (char*)pVoid; //OK in both C and C++
pChar = pVoid; //OK in C, convertion is implicit
回答by octopusgrabbus
I just tried your code in a module called temp.c. I added a function called f1.
我刚刚在名为 temp.c 的模块中尝试了您的代码。我添加了一个名为 f1 的函数。
void *pa; void *pb;
char *ptemp; char *ptemp2;
f1()
{
ptemp = (char *)pa;
ptemp2 = (char *)pb;
}
On Linux I entered gcc -c temp.c, and this compiled with no errors or warnings.
在 Linux 上，我输入了 gcc -c temp.c，并且编译时没有错误或警告。
On which OS are you trying this?
你在哪个操作系统上尝试这个？
