Python 在 Django 中与众不同
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时间:2020-08-18 20:34:30 来源:igfitidea点击:
DISTINCT ON in django
提问by David542
How would I do the following query:
我将如何执行以下查询:
OrderNotes.objects.filter(item=item).distinct('shared_note')
Basically, I need to get all OrderNotesitems, distinct on shared_note. When I try and do this I get:
基本上,我需要获取所有OrderNotes项目,在shared_note. 当我尝试这样做时,我得到:
raise NotImplementedError('DISTINCT ON fields is not supported by this database backend')
NotImplementedError: DISTINCT ON fields is not supported by this database backend
I am using mysql and cannot change the db here. What would be the workaround in django?
我正在使用 mysql 并且无法在此处更改数据库。Django 中的解决方法是什么?
采纳答案by catherine
OrderNotes.objects.filter(item=item).values_list('shared_note', flat=True).distinct()
回答by David542
This is the best I came up with:
这是我想出的最好的:
>>> items, item_ids = [], []
>>> for item in OrderNotes.objects.filter(shared_note=219):
... if item.shared_note not in item_ids:
... items.append(item)
... item_ids.append(item.shared_note)

![IOError: [Errno 22] 无效模式 ('r') 或文件名: 'c:\\Python27\test.txt'](/res/img/loading.gif)