从 Java 中的 URL/路径中删除文件名
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/21829295/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Remove filename from a URL/Path in java
提问by Yemto
How do I remove the file name from a URL or String?
如何从 URL 或字符串中删除文件名？
String os = System.getProperty("os.name").toLowerCase();
String nativeDir = Game.class.getProtectionDomain().getCodeSource().getLocation().getFile().toString();
//Remove the <name>.jar from the string
if(nativeDir.endsWith(".jar"))
nativeDir = nativeDir.substring(0, nativeDir.lastIndexOf("/"));
//Load the right native files
for(File f : (new File(nativeDir + File.separator + "lib" + File.separator + "native")).listFiles()){
if(f.isDirectory() && os.contains(f.getName().toLowerCase())){
System.setProperty("org.lwjgl.librarypath", f.getAbsolutePath()); break;
}
}
That's what I have right now, and it work. From what I know, because I use "/" it will only work for windows. I want to make it platform independent
这就是我现在所拥有的，并且有效。据我所知，因为我使用“/”，所以它只适用于 Windows。我想让它独立于平台
回答by Chthonic Project
Instead of "/", use File.separator. It is either /or \, depending on the platform. If this is not solving your issue, then use FileSystem.getSeparator(): you can pass different filesystems, instead of the default.
而不是“/”，使用File.separator. 它是/或\，具体取决于平台。如果这不能解决您的问题，请使用FileSystem.getSeparator(): 您可以传递不同的文件系统，而不是默认值。
回答by Dirk Fauth
You are using File.separator in another line. Why not using it also for your lastIndexOf()?
您在另一行中使用 File.separator。为什么不将它也用于 lastIndexOf()？
nativeDir = nativeDir.substring(0, nativeDir.lastIndexOf(File.separator));
回答by PopoFibo
Consider using org.apache.commons.io.FilenameUtils
考虑使用org.apache.commons.io.FilenameUtils
You can extract the base path, file name, extensions etc with any flavor of file separator:
您可以使用任何形式的文件分隔符提取基本路径、文件名、扩展名等：
String url = "C:\windows\system32\cmd.exe";
String baseUrl = FilenameUtils.getPath(url);
String myFile = FilenameUtils.getBaseName(url)
+ "." + FilenameUtils.getExtension(url);
System.out.println(baseUrl);
System.out.println(myFile);
Gives,
给，
windows\system32\
cmd.exe
With url; String url = "C:/windows/system32/cmd.exe";
带网址； String url = "C:/windows/system32/cmd.exe";
It would give;
它会给;
windows/system32/
cmd.exe
回答by Ksi?dz Pistolet
I solve this problem using regex.
我使用正则表达式解决了这个问题。
For windows:
对于窗户：
String path = "";
String filename = "d:\folder1\subfolder11\file.ext";
String regEx4Win = "\\(?=[^\\]+$)";
String[] tokens = filename.split(regEx4Win);
if (tokens.length > 0)
path = tokens[0]; // path -> d:\folder1\subfolder11
回答by Jeremy Sigrist
The standard library can handle this as of Java 7
从 Java 7 开始，标准库就可以处理这个问题
Path pathOnly;
if (file.getNameCount() > 0) {
pathOnly = file.subpath(0, file.getNameCount() - 1);
} else {
pathOnly = file;
}
fileFunction.accept(pathOnly, file.getFileName());
回答by saygley
By utilizing java.nio.file; (afaik introduced after J2SE 1.7) this simply solved my problem:
通过使用java.nio.file；（afaik 在 J2SE 1.7 之后引入）这简单地解决了我的问题：
Path path = Paths.get(fileNameWithFullPath);
String directory = path.getParent().toString();
