函数名在python类中未定义
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function name is undefined in python class
提问by aceminer
I am relatively new to python and i am experiencing some issues with namespacing.
我对 python 比较陌生，我在命名空间方面遇到了一些问题。
class a:
def abc(self):
print "haha"
def test(self):
abc()
b = a()
b.abc() #throws an error of abc is not defined. cannot explain why is this so
采纳答案by Paul Lo
Since test()doesn't know who is abc, that msg NameError: global name 'abc' is not definedyou see should happen when you invoke b.test()(calling b.abc()is fine), change it to:
由于test()不知道 who is abc，NameError: global name 'abc' is not defined您看到的msg应该在您调用时发生b.test()（调用b.abc()很好），请将其更改为：
class a:
def abc(self):
print "haha"
def test(self):
self.abc()
# abc()
b = a()
b.abc() # 'haha' is printed
b.test() # 'haha' is printed
回答by Beri
In order to call method from the same class, you need the selfkeyword.
为了从同一个类调用方法，你需要self关键字。
class a:
def abc(self):
print "haha"
def test(self):
self.abc() // will look for abc method in 'a' class
Without the selfkeyword, python is looking for the abcmethod in the global scope, that is why you are getting this error.
如果没有self关键字，python 会abc在全局范围内查找该方法，这就是您收到此错误的原因。
