Python 为 os.listdir 返回的文件名提供 FileNotFoundError
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Python giving FileNotFoundError for file name returned by os.listdir
提问by Aarushi Mishra
I was trying to iterate over the files in a directory like this:
我试图遍历目录中的文件，如下所示：
import os
path = r'E:/somedir'
for filename in os.listdir(path):
f = open(filename, 'r')
... # process the file
But Python was throwing FileNotFoundErroreven though the file exists:
但是FileNotFoundError即使文件存在，Python也会抛出：
Traceback (most recent call last):
File "E:/ADMTM/TestT.py", line 6, in <module>
f = open(filename, 'r')
FileNotFoundError: [Errno 2] No such file or directory: 'foo.txt'
So what is wrong here?
那么这里有什么问题呢？
采纳答案by Antti Haapala
It is because os.listdirdoes not return the full path to the file, only the filename part; that is 'foo.txt', when open would want 'E:/somedir/foo.txt'because the file does not exist in the current directory.
这是因为os.listdir不返回文件的完整路径，只返回文件名部分；也就是说'foo.txt'，当打开时会想要，'E:/somedir/foo.txt'因为当前目录中不存在该文件。
Use os.path.jointo prepend the directory to your filename:
用于os.path.join将目录添加到您的文件名中：
path = r'E:/somedir'
for filename in os.listdir(path):
with open(os.path.join(path, filename)) as f:
... # process the file
(Also, you are not closing the file; the withblock will take care of it automatically).
（此外，您没有关闭文件；with块将自动处理它）。
回答by Lukas Graf
os.listdir(directory)returns a list of file namesin directory. So unless directoryis your current working directory, you need to join those file names with the actual directory to get a proper absolute path:
os.listdir(directory)返回文件列表的名称在directory。因此，除非directory是您当前的工作目录，否则您需要将这些文件名与实际目录连接起来以获得正确的绝对路径：
for filename in os.listdir(path):
filepath = os.path.join(path, filename)
f = open(filepath,'r')
raw = f.read()
# ...
