typescript 类型化的函数数组
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A Typed array of functions
提问by Matt Burland
I'm struggling to figure out if it's possible in TypeScript to declare a statically typed array of functions.
我正在努力弄清楚是否可以在 TypeScript 中声明一个静态类型的函数数组。
For example, I can do this:
例如，我可以这样做：
foo: (data:string) => void = function (data) {};
But if I want foo to be an array of functions that take a string and return nothing, how do I do that?
但是如果我想让 foo 成为一个接受字符串并且不返回任何内容的函数数组，我该怎么做？
foo: (data:string) => void [] = [];
Doesn't work because TypeScript thinks it's a function that takes a string and returns an array of void, and it doesn't seem to like me trying to wrap the function in brackets.
不起作用，因为 TypeScript 认为它是一个函数，它接受一个字符串并返回一个 void 数组，而且它似乎不喜欢我试图将函数包装在括号中。
Any ideas?
有任何想法吗？
Answer: Thanks to mohamed below, here's an example that works in the TypeScript Playground:
答：感谢下面的 mohamed，这是一个在 TypeScript Playground 中有效的示例：
class whatever {
public foo: { (data: string): void; }[] = [];
dofoo() {
for (var i=0; i < this.foo.length; i++) {
this.foo[i]("test");
}
}
}
var d = new whatever();
d.foo.push(function(bar){alert(bar)})
d.foo.push(function(bar){alert(bar.length.toString())})
d.dofoo();
回答by mohamed hegazy
You can find this in the language specsection 3.5.5:
您可以在语言规范第 3.5.5 节中找到它：
foo: { (data: string): void; } []
回答by Saravana
Other (newer, more readable) ways to type an array of functions using fat arrows:
使用粗箭头键入函数数组的其他（更新的、更易读的）方法：
let foo: Array<(data: string) => void>;
let bar: ((data: string) => void)[];
回答by aaron
or foo: ((data: string) => void)[]
或者 foo: ((data: string) => void)[]
回答by Janderson Silva
If you wish declare an array of callable function in TypeScript, you can declare a type:
如果你想在 TypeScript 中声明一个可调用函数数组，你可以声明一个类型：
type Bar = (
(data: string) => void
);
And then use it:
然后使用它：
const foo: Bar[] = [];
const fooFn = (data: string) => console.log(data);
foo.push(fooFn);
foo.forEach((fooFn: Bar) => fooFn("Something");
