Python BeautifulSoup findAll 通过“class”属性
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/19969056/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Python BeautifulSoup findAll by "class" attribute
提问by appleLover
I want to do the following code, which is what BS documentation says to do, the only problem is that the word "class" isn't just a word. It can be found inside HTML, but it's also a python keyword which causes this code to throw an error.
我想做下面的代码，这是 BS 文档所说的，唯一的问题是“类”这个词不仅仅是一个词。它可以在 HTML 中找到，但它也是一个导致此代码抛出错误的 python 关键字。
So how do I do the following?
那么我该怎么做呢？
soup.findAll('ul', class="score")
回答by aIKid
Here is how to do it:
这是如何做到的：
soup.find_all('ul', {'class':"score"})
回答by mattexx
Your problem seems to be that you expect find_allin the soup to find an exact match for your string. In fact:
您的问题似乎是您希望find_all在汤中找到与您的字符串完全匹配的字符串。事实上：
When you search for a tag that matches a certain CSS class, you're matching against any of its CSS classes:
当您搜索与某个 CSS 类匹配的标签时，您将匹配其任何 CSS 类：
You can properly search for a class tag as @alKid said. You can also search with the class_keyword arg.
您可以像@alKid 所说的那样正确搜索类标签。您还可以使用class_关键字 arg 进行搜索。
soup.find_all('ul', class_="score")
