bash 如何判断“find”命令的输出是否为空？
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How to tell if the output of the "find" command is empty?
提问by cstack
I want to return an exit status of 0 if the output is empty and 1 otherwise:
如果输出为空，我想返回 0 的退出状态，否则返回 1：
find /this/is/a/path/ -name core.*
回答by Rob Davis
When you say you want it to return a particular number, are you referring to the exit status? If so:
当你说你想要它返回一个特定的数字时，你指的是退出状态吗？如果是这样的话：
[[ -z `find /this/is/a/path/ -name core.*` ]]
And since you only care about a yes/no response, you may want to change your find to this:
并且由于您只关心是/否响应，您可能希望将您的发现更改为：
[[ -z `find /this/is/a/path/ -name core.* -print -quit` ]]
which will stop after the first core file found. Without that, if the root directory is large, the find could take a while.
这将在找到第一个核心文件后停止。如果没有它，如果根目录很大，查找可能需要一段时间。
回答by Alex Howansky
Here's my version. :)
这是我的版本。:)
[ -z "$(find /this/is/a/path/ -name 'core.*')" ] && true
Edited for brevity:
为简洁起见编辑：
[ -z "$(find /this/is/a/path/ -name 'core.*')" ]
回答by Peter Eisentraut
There are probably many variants, but this is one:
可能有很多变体，但这是一个：
test $(find /this/is/a/path/ -name core.* | wc -c) -eq 0
回答by Steven Penny
Perhaps this
也许这
find /this/is/a/path/ -name 'core.*' | read
回答by Thomas Rassloff
I am using this:
我正在使用这个：
if test $(find $path -name value | wc -c) -eq 0
then
echo "has no value"
exit
else
echo "perfect !!!"
fi
