bash 如何将字符串的每个字母移动给定数量的字母？
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How to shift each letter of the string by a given number of letters?
提问by Euphorbium
How can i shift each letter of a string by a given number of letters down or up in bash, without using a hardcoded dictionary?
如何在不使用硬编码字典的情况下在 bash 中将字符串的每个字母向下或向上移动给定数量的字母？
回答by paxdiablo
Do you mean something like ROT13:
你的意思是像 ROT13：
pax$ echo 'hello there' | tr '[a-z]' '[n-za-m]'
uryyb gurer
pax$ echo 'hello there' | tr '[a-z]' '[n-za-m]' | tr '[a-z]' '[n-za-m]'
hello there
For a more general solution where you want to provide an arbitrary rotation (0 through 26), you can use:
对于要提供任意旋转（0 到 26）的更通用的解决方案，您可以使用：
#!/usr/bin/bash
dual=abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyz
phrase='hello there'
rotat=13
newphrase=$(echo $phrase | tr "${dual:0:26}" "${dual:${rotat}:26}")
echo ${newphrase}
回答by Ignacio Vazquez-Abrams
$ alpha=abcdefghijklmnopqrstuvwxyz
$ rot=3
$ sed "y/${alpha}/${alpha:$rot}${alpha::$rot}/" <<< 'foobar'
irredu
回答by gmagno
If you want to rotate also the capitals you could use something like this:
如果你还想旋转大写字母，你可以使用这样的东西：
cat data.txt | tr '[a-z]' '[n-za-m]' | tr '[A-Z]' '[N-ZA-M]'
where data.txt has whatever you want to rotate.
其中 data.txt 包含您想要旋转的任何内容。
