C++ 静态成员函数错误;如何正确书写签名?
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Static member functions error; How to properly write the signature?
提问by Joshua
I am getting an error when trying to compile my code in g++ using the current signature:
尝试使用当前签名在 g++ 中编译我的代码时出现错误:
cannot declare member function static void Foo::Bar(std::ostream&, const Foo::Node*) to have static linkage
My question is twofold:
我的问题是双重的:
- Why does it not Compile this way?
- What is the correct signature, and why?
- 为什么不这样编译?
- 什么是正确的签名,为什么?
Signatures have always been the death of me when using C++
使用 C++ 时,签名一直是我的死因
Edit: Here is the class header file, as well:
编辑:这里也是类头文件:
class Foo {
public:
Foo();
~Foo();
bool insert(const Foo2 &v);
Foo * find(const Foo2 &v);
const Foo * find(const Foo2 &v) const;
void output(ostream &s) const;
private:
//Foo(const Foo &v);
//Foo& operator =(const Foo &v);
//Not implemented; unneeded
struct Node {
Foo2 info;
Node *left;
Node *right;
};
Node * root;
static bool insert(const Foo2 &v, Node *&p);
static void output(ostream &s, const Node *p);
static void deleteAll(Node *p);
回答by Oliver Charlesworth
I'm guessing you've done something like:
我猜你已经做了类似的事情:
class Foo
{
static void Bar();
};
...
static void Foo::Bar()
{
...
}
The "static void Foo::Bar
" is incorrect. You don't need the second "static
".
“ static void Foo::Bar
”不正确。你不需要第二个“ static
”。