ruby 将数组的内容转换为 int
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Convert contents of an array to int
提问by Benoit Garret
I need to read in a file of which contains a list of numbers.
我需要读入一个包含数字列表的文件。
This code reads in the file and puts it into a 2d array. Now I need to get the average of all the numbers in my array but I need to change the contents of the array to int. Any ideas where to put the to_imethod?
此代码读入文件并将其放入二维数组中。现在我需要获得数组中所有数字的平均值，但我需要将数组的内容更改为 int。任何想法把to_i方法放在哪里？
Class Terrain
def initialize file_name
@input = IO.readlines(file_name) #read in file
@size = @input[0].to_i
@land = [@size]
x = 1
while x <= @size
@land << @input[x].split(/\s/)
x += 1
end
#puts @land
end
end
回答by Benoit Garret
Just map your array to integers:
只需将您的数组映射到整数：
@land << @input[x].split(/\s/).map(&:to_i)
side note
边注
If you want to get the average of a line, you can do the following:
如果您想获得一条线的平均值，您可以执行以下操作：
values = @input[x].split(/\s/).map(&:to_i)
@land << values.inject(0.0) {|sum, item| sum + item} / values.size
or use the following, as Marc-Andrékindly pointed out in the comments:
或使用以下内容，正如Marc-André在评论中亲切指出的那样：
values = @input[x].split(/\s/).map(&:to_i)
@land << values.inject(0.0, :+) / values.size
回答by Bhushan Lodha
did you try
你试过了吗
@land << @input[x].split(/\s/).strip.to_i
