Linux bash脚本在文本文件中查找模式并返回整行
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bash script to find pattern in text file and return entire line
提问by Sally Sasquatch
I need to make a bash script which loops through a bunch of .txt files in a directory, then searches each .txt for a string, and returns the entire line that string appears on
我需要制作一个 bash 脚本，它循环遍历目录中的一堆 .txt 文件，然后在每个 .txt 中搜索一个字符串，并返回该字符串出现的整行
I know how to look through all the .txt files in the directory,
我知道如何查看目录中的所有 .txt 文件，
I just need to be pointed in the right direction for searching the file itself, and returning a line based on a match in that line
我只需要指向正确的方向来搜索文件本身，并根据该行中的匹配返回一行
回答by amit_g
Within one dir
一个目录内
grep "search string" *.txt
Search or go to sub-dir
搜索或转到子目录
find /full/path/to/dir -name "*.txt" -exec grep "search string" {} ;\
回答by Matt
you can use a loop:
您可以使用循环：
for i in $(find|grep .txt); do grep "search" "$i";If you also want to print the filename with each match, add -Hto grep
for i in $(find|grep .txt); do grep "search" "$i";如果您还想打印每个匹配项的文件名，请添加-H到 grep
回答by Bryan
One slight addition. Add -nto return the line.
一点点补充。添加-n以返回行。
grep -rn "foo" *.txt
See grep --helpfor more.
查看grep --help更多。
