bash 将结果从 FIND 命令导出到 linux shell 脚本中的变量值？
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Export result from FIND command to variable value in linux shell script?
提问by black_hat_cat
I try to complete one shell script, but I don't have idea how to do final, and probably easiest step.
我尝试完成一个 shell 脚本，但我不知道如何完成最后一步，也可能是最简单的一步。
That is attaching value to variable from find command.
那是将值附加到 find 命令中的变量。
For example, if I execute:
例如，如果我执行：
find -type f -iname *test.tdf*
I will get output in example:
我将在示例中获得输出：
/root/Desktop/test.tdf
Now, I need a way to attach that value to for example:
现在，我需要一种方法来将该值附加到例如：
export PATH_TO_TEST_TDF_FILE=/root/Desktop/test.tdf
But now, problem is that file may not be located there, so I must assign it to result from find.
但是现在，问题是文件可能不在那里，所以我必须将它分配给 find 的结果。
How?
如何？
回答by iruvar
If your findinvocation outputs a single file along the lines of what you have shown, command substitutionshould do the trick
如果您的find调用按照您显示的内容输出单个文件，则命令替换应该可以解决问题
export PATH_TO_TEST_TDF_FILE="$(find . -type f -iname '*test.tdf*')"
Or, as BroSlowpoints out,
或者，正如BroSlow指出的那样，
export PATH_TO_TEST_TDF_FILE="$(find . -type f -iname '*test.tdf*' -print -quit)"
to have findquit after the first file
已经find第一个文件后退出
回答by Joshua
Would be PATH_TO_TEST_TDF_FILE="$(find -type f -iname test.tdf)" but probably doesn't work too well as find returns more than one file most of the time.
将是 PATH_TO_TEST_TDF_FILE="$(find -type f -iname test.tdf)" 但可能效果不佳，因为 find 大部分时间都返回多个文件。
Pro tip: The results of find should be assumed to not fit in a variable until proven otherwise.
专业提示：应该假设 find 的结果不适合变量，除非另有证明。
