Java中的Base64字符串到字节[]
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Base64 String to byte[] in java
提问by Ninad Kulkarni
I am trying to convert base64 String to byte array but it is throwing following error
我正在尝试将 base64 字符串转换为字节数组，但它抛出以下错误
java.lang.IllegalArgumentException: Illegal base64 character 3a
java.lang.IllegalArgumentException: 非法 base64 字符 3a
I have tried following options userimage is base64 string
我试过以下选项 userimage 是 base64 字符串
byte[] img1 = org.apache.commons.codec.binary.Base64.decodeBase64(userimage);`
/* byte[] decodedString = Base64.getDecoder().decode(encodedString.getBytes(UTF_8));*/
/* byte[] byteimage =Base64.getDecoder().decode( userimage );*/
/* byte[] byteimage = Base64.getMimeDecoder().decode(userimage);*/`
采纳答案by Ravi Koradia
You can use java.util.Base64package to decode the String to byte[].
Below code which I have used for encode and decode.
您可以使用java.util.Base64package 将字符串解码为byte[]. 下面是我用于编码和解码的代码。
For Java 8 :
对于 Java 8：
import java.io.UnsupportedEncodingException;
import java.util.Base64;
public class Example {
public static void main(String[] args) {
try {
byte[] name = Base64.getEncoder().encode("hello World".getBytes());
byte[] decodedString = Base64.getDecoder().decode(new String(name).getBytes("UTF-8"));
System.out.println(new String(decodedString));
} catch (UnsupportedEncodingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
For Java 6 :
对于 Java 6：
import java.io.UnsupportedEncodingException;
import org.apache.commons.codec.binary.Base64;
public class Main {
public static void main(String[] args) {
try {
byte[] name = Base64.encodeBase64("hello World".getBytes());
byte[] decodedString = Base64.decodeBase64(new String(name).getBytes("UTF-8"));
System.out.println(new String(decodedString));
} catch (UnsupportedEncodingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
