Python 从时间中减去小时和分钟
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Subtract hours and minutes from time
提问by Sachhya
In my task what I need to do is to subtract some hours and minutes like (0:20,1:10...any value) from time (2:34 PM) and on the output side I need to display the time after subtraction. time and hrs:minutes value are hardcoded
在我的任务中，我需要做的是从时间（下午 2:34）中减去一些小时和分钟（0:20,1:10...任何值），在输出端我需要显示时间减法。time 和 hrs:minutes 值是硬编码的
Ex:
前任：
my_time = 1:05 AM
my_time = 1:05 AM
duration = 0:50
持续时间 = 0:50
so output should be 12:15 PM
所以输出应该是 12:15 PM
Output should be exact and in AM/PM Format and Applicable for all values [ 0:00 < Duration > 6:00 ]
输出应准确，采用 AM/PM 格式，适用于所有值 [ 0:00 < Duration > 6:00 ]
And don't care about seconds only hrs and minutes parts needed
并且不关心秒只需要几小时和几分钟的零件
回答by asfarto
from datetime import datetime, timedelta
d = datetime.today() - timedelta(hours=0, minutes=50)
d.strftime('%H:%M %p')
回答by Taniya
This worked for me :
这对我有用：
from datetime import datetime
s1 = '10:04:00'
s2 = '11:03:11' # for example
format = '%H:%M:%S'
time = datetime.strptime(s2, format) - datetime.strptime(s1, format)
print time
回答by Fuzed Mass
from datetime import datetime
d1 = datetime.strptime("01:05:00.000", "%H:%M:%S.%f")
d2 = datetime.strptime("00:50:00.000", "%H:%M:%S.%f")
print (d1-d2)
