Bash 脚本 - 迭代 find 的输出
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Bash Script - iterating over output of find
提问by Nate Mara
I have a bash script in which I need to iterate over each line of the ouput of the find command, but it appears that I am iterating over each Word (space delimited) from the find command. My script looks like this so far:
我有一个 bash 脚本，我需要在其中遍历 find 命令输出的每一行，但似乎我正在遍历 find 命令中的每个 Word（空格分隔）。到目前为止，我的脚本如下所示：
folders=`find -maxdepth 1 -type d`
for $i in $folders
do
echo $i
done
I would expect this to give output like:
我希望这会给出如下输出：
./dir1 and foo
./dir2 and bar
./dir3 and baz
But I am insted getting output like this:
但是我得到了这样的输出：
./dir1
and
foo
./dir2
and
bar
./dir3
and
baz
What am I doing wrong here?
我在这里做错了什么？
回答by Charles Duffy
folders=`foo`
is always wrong, because it assumes that your directories won't contain spaces, newlines (yes, they're valid!), glob characters, etc. One robust approach (which requires the GNU extension -print0) follows:
总是错误的，因为它假设您的目录不包含空格、换行符（是的，它们是有效的！）、glob 字符等。一种强大的方法（需要 GNU 扩展-print0）如下：
while IFS='' read -r -d '' filename; do
: # something with "$filename"
done < <(find . -maxdepth 1 -type d -print0)
Another safe and robust approach is to have finditself directly invoke your desired command:
另一种安全可靠的方法是让find自己直接调用您想要的命令：
find . -maxdepth 1 -type d -exec printf '%s\n' '{}' +
See the UsingFindwiki page for a complete treatment of the subject.
回答by chepner
Since you aren't using any of the more advanced features of find, you can use a simple pattern to iterate over the subdirectories:
由于您没有使用 的任何更高级的功能find，您可以使用一个简单的模式来遍历子目录：
for i in ./*/; do
echo "$i"
done
回答by Малъ Скрылевъ
You can do something like this:
你可以这样做：
find -maxdepth 1 -type d | while read -r i
do
echo "$i"
done
