pandas 熊猫数据框，按值复制
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pandas dataframe, copy by value
提问by Andrew
I noticed a bug in my program and the reason it is happening is because it seems that pandas is copying by reference a pandas dataframe instead of by value. I know immutable objects will always be passed by reference but pandas dataframe is not immutable so I do not see why it is passing by reference. Can anyone provide some information?
我注意到我的程序中有一个错误，它发生的原因是因为Pandas似乎是通过引用Pandas数据帧而不是值来复制的。我知道不可变对象总是通过引用传递，但 Pandas 数据帧不是不可变的，所以我不明白它为什么通过引用传递。谁能提供一些信息？
Thanks! Andrew
谢谢！安德鲁
回答by Wes McKinney
All functions in Python are "pass by reference", there is no "pass by value". If you want to make an explicit copy of a pandas object, try new_frame = frame.copy().
Python中的所有函数都是“按引用传递”，没有“按值传递”。如果你想制作一个 Pandas 对象的显式副本，请尝试new_frame = frame.copy().
