string 用 + 替换字符串中的所有空格
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Replace all spaces in a string with +
提问by Micheal Perr
I have a string and I want to replace every space in this string with a + I tired this by using:
我有一个字符串，我想用 + 替换这个字符串中的每个空格，我厌倦了使用：
tw.Text = strings.Replace(tw.Text, " ", "+", 1)
But that didn't worked for me...any solutions?
但这对我不起作用......有任何解决方案吗？
For example the string could look like:
例如，字符串可能如下所示：
The answer of the universe is 42
回答by MikeM
Update:Since go 1.12, please use strings.ReplaceAll(s, old, new string)func ReplaceAll
更新：从 go 1.12 开始，请使用strings.ReplaceAll(s, old, new string)func ReplaceAll
from the Go documentation: func Replace
来自 Go 文档：func Replace
If n < 0, there is no limit on the number of replacements.
如果 n < 0，则替换次数没有限制。
try
尝试
strings.Replace(tw.Text, " ", "+", -1)
回答by C???
Documentation on strings.Replace(): http://golang.org/pkg/strings/#Replace
文档strings.Replace()：http: //golang.org/pkg/strings/#Replace
According to the documentation, the fourth integer parameter is the number of replacements. Your example would only replace the first space with a "+". You need to use a number less than 0 for it to not impose a limit:
根据文档，第四个整数参数是替换次数。您的示例只会用“+”替换第一个空格。您需要使用小于 0 的数字才能不施加限制：
tw.Text = strings.Replace(tw.Text, " ", "+", -1)
回答by imgrgry
If you are using this in a query, the QueryEscapemethod provided by net/urlis the best solution: https://golang.org/pkg/net/url/#QueryEscape
如果你在查询中使用这个，QueryEscape提供的方法net/url是最好的解决方案：https: //golang.org/pkg/net/url/#QueryEscape
import "net/url"
tw.Text = url.QueryEscape(tw.Text)
