命令行（或批处理文件）重命名文件夹中的所有文件 (Windows)
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Command Line (or batch file) rename all files in a folder (Windows)
提问by MartinaL
I need to rename all of the files in a folder with the following filename format;
我需要使用以下文件名格式重命名文件夹中的所有文件；
itemID-straight-bottle.png
itemID-straight-bottle.png
TO
到
itemID-bottle.png
itemID-bottle.png
How can i accomplish this with a cmd script or in the command line?
如何使用 cmd 脚本或在命令行中完成此操作？
example;
例子;
REDHI20806-straight-bottle.png TO REDHI20806-bottle.png
REDHI20806-straight-bottle.png 到 REDHI20806-bottle.png
I should have said, this is in Windows and i want to use either command line or a batch file to run this renaming on all files in a folder on a specific drive
我应该说，这是在 Windows 中，我想使用命令行或批处理文件在特定驱动器上的文件夹中的所有文件上运行此重命名
回答by tolitius
short answer
简答
On Windows, you can use PowerShell, that is installed by default on Windows 7, and can be downloaded and installed on previous versions. With PowerShell you can do the rename as:
在Windows 上，您可以使用 Windows 7 上默认安装的 PowerShell，并且可以在以前的版本上下载和安装。使用 PowerShell，您可以将重命名为：
ls | foreach-object -process {ren $_ (%{$_ -replace "-straight",""})}
On Unix/Linux, nothing specific needs to be installed, and you can do the rename as:
在Unix/Linux 上，不需要安装任何特定的东西，您可以将重命名为：
ls | awk '{print("mv "" ")}' | cut -f -3,5- -d '-' | sh
examples
例子
Windows Example
Windows 示例
Given
给定的
PS C:\rename-me> ls
Directory: C:\rename-me
Mode LastWriteTime Length Name
---- ------------- ------ ----
-a--- 10/9/2011 1:35 PM 0 REDHI20806-straight-bottle.png
-a--- 10/9/2011 1:35 PM 0 REDHI20807-straight-bottle.png
-a--- 10/9/2011 1:35 PM 0 REDHI20808-straight-bottle.png
-a--- 10/9/2011 1:35 PM 0 REDHI20809-straight-bottle.png
-a--- 10/9/2011 1:35 PM 0 REDHI20810-straight-bottle.png
Doing It
正在做
PS C:\rename-me> ls | foreach-object -process {ren $_ (%{$_ -replace "-straight",""})}
Result
结果
PS C:\rename-me> ls
Directory: C:\rename-me
Mode LastWriteTime Length Name
---- ------------- ------ ----
-a--- 10/9/2011 1:35 PM 0 REDHI20806-bottle.png
-a--- 10/9/2011 1:35 PM 0 REDHI20807-bottle.png
-a--- 10/9/2011 1:35 PM 0 REDHI20808-bottle.png
-a--- 10/9/2011 1:35 PM 0 REDHI20809-bottle.png
-a--- 10/9/2011 1:35 PM 0 REDHI20810-bottle.png
Unix/Linux Example
Unix/Linux 示例
Given
给定的
$ ls -l
total 0
-rw-r--r-- 1 user staff 0 Oct 7 00:54 REDHI20806-straight-bottle.png
-rw-r--r-- 1 user staff 0 Oct 7 00:54 REDHI20807-straight-bottle.png
-rw-r--r-- 1 user staff 0 Oct 7 00:54 REDHI20808-straight-bottle.png
-rw-r--r-- 1 user staff 0 Oct 7 00:54 REDHI20809-straight-bottle.png
-rw-r--r-- 1 user staff 0 Oct 7 00:54 REDHI20810-straight-bottle.png
Doing It
正在做
$ ls | awk '{print("mv "" ")}' | cut -f -3,5- -d '-' | sh
Result
结果
$ ls -l
total 0
-rw-r--r-- 1 user staff 0 Oct 7 00:54 REDHI20806-bottle.png
-rw-r--r-- 1 user staff 0 Oct 7 00:54 REDHI20807-bottle.png
-rw-r--r-- 1 user staff 0 Oct 7 00:54 REDHI20808-bottle.png
-rw-r--r-- 1 user staff 0 Oct 7 00:54 REDHI20809-bottle.png
-rw-r--r-- 1 user staff 0 Oct 7 00:54 REDHI20810-bottle.png
回答by wimh
if only the last part of the filename (straight-bottle.png) needs to change (to bottle.png) you can simply do this:
如果只有文件名 ( straight-bottle.png)的最后一部分需要更改 ( to bottle.png) 您可以简单地执行以下操作：
REN ??????????-straight-bottle.png ??????????-bottle.png
(I did not test this though)
（虽然我没有测试这个）
