C语言 从类型“char *”分配给类型“char[128]”时的类型不兼容
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原文地址: http://stackoverflow.com/questions/17463487/
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incompatible types when assigning to type 'char[128]' from type 'char *'
提问by Elad Benda
I'm trying to assign char* field to char* field, but get this error:
我正在尝试将 char* 字段分配给 char* 字段，但出现此错误：
incompatible types when assigning to type 'char[128]' from type 'char *'
incompatible types when assigning to type 'char[128]' from type 'char *'
how can I fix this? and why is that happening?
我怎样才能解决这个问题？为什么会这样？
AddressItem_Callback_ContextType *context = (AddressItem_Callback_ContextType *)malloc(sizeof(AddressItem_Callback_ContextType));
//check if icons need to be downloaded
if (pEntity->cBigIcon[0] != 0){
if (res_get(RES_BITMAP,RES_SKIN, pEntity->cBigIcon) == NULL){
context->Icon = pEntity->cBigIcon;
context->iID = pEntity->iID;
res_download(RES_DOWNLOAD_IMAGE, pEntity->cBigIcon, NULL, "",TRUE, 1, addressItem_icon_download_callback, context );
}
}
declarations:
声明：
typedef struct
{
int iID; // POI Type ID
int iExternalPoiServiceID; // Service ID
int iExternalPoiProviderID; // Provider ID
char cBigIcon[MAX_ICON_LENGHT];
char cSmallIcon[MAX_ICON_LENGHT];
char cBigPromotionIcon[MAX_ICON_LENGHT];
char cSmallPromotionIcon[MAX_ICON_LENGHT];
char cOnClickUrl[MAX_URL_LENGTH];
..
} RTExternalPoiType;
typedef struct
{
int iID; // POI Type ID
//int iExternalPoiServiceID; // Service ID
// int iExternalPoiProviderID; // Provider ID
char Icon[MAX_ICON_LENGHT];
} AddressItem_Callback_ContextType;
采纳答案by Amit Bhaira
Array names are constant pointers you can not modify them. In this scenario Icon is a constant pointer and
数组名称是常量指针，您无法修改它们。在这种情况下 Icon 是一个常量指针和
context->Icon = pEntity->cBigIcon;
here you are trying to modify it, which is not allowed.
在这里你试图修改它，这是不允许的。
Try this ..
尝试这个 ..
strcpy(context->Icon,pEntity->cBigIcon);
strcpy(context->Icon,pEntity->cBigIcon);
回答by
You can't assign to arrays (as the error message states). Copythe strings instead:
您不能分配给数组（如错误消息所述）。改为复制字符串：
snprintf(aStruct->member, sizeof(aStruct->member), "%s", someString);
Or, if you want to shoot yourself in the foot (prone to buffer overruns):
或者，如果您想用脚射击自己（容易发生缓冲溢出）：
strcpy(aStruct->member, "the string");
Or, if you want to shoot yourself in the foot and not notice it (safe of buffer overruns, but doesn't NUL-terminate the string if too long):
或者，如果您想用脚射击而没有注意到它（缓冲区溢出是安全的，但如果太长，则不会以 NUL 终止字符串）：
strncpy(aStruct->member, "the string", sizeof(aStruct->member));
