在python 2.7中删除_之前和包括_的字符
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Remove characters before and including _ in python 2.7
提问by user2343368
The following code returns into a nice readable output.
以下代码返回一个很好的可读输出。
def add_line_remove_special(ta_from,endstatus,*args,**kwargs):
try:
ta_to = ta_from.copyta(status=endstatus)
infile = botslib.opendata(ta_from.filename,'r')
tofile = botslib.opendata(str(ta_to.idta),'wb')
start = infile.readline()
import textwrap
lines= "\r\n".join(textwrap.wrap(start, 640))
tofile.write(lines)
infile.close()
tofile.close()
This is the output, now I would like to remove all the characters until and including the _
这是输出，现在我想删除所有字符，直到并包括 _
Ichg_UNBUNOA3 14 2090100000015 14 1304221445000001
MSG_BGM380 610809 9 NA
MSG_DTM13720130422 102
Grp1_RFFON test EDI
Grp2_NADBY 2090100000015 9
Grp2_NADIV 2090100000015 9
Grp2_NADDP 2090100000015 9
Grp7_CUX2 EUR4
Grp8_PAT22 5 3 D 30
Grp25_LIN1 02090100000022 EN
Grp25_QTY47 5
Grp25_QTY12 5
Grp26_MOA203 15.00
Grp28_PRIINV 3000.00 1000PCE
Grp33_TAX7 VAT 21.00 S
Grp25_LIN2 02090100000039 EN
Grp25_QTY47 10
Grp25_QTY12 10
Grp26_MOA203 350.00
Grp28_PRIINV 35000.00 1000PCE
Grp33_TAX7 VAT 21.00 S
How can I do this?
我怎样才能做到这一点？
采纳答案by Martijn Pieters
To get all text on a line after a underscore character, split on the first _character and take the last element of the result:
要获取下划线字符后一行上的所有文本，请拆分第一个_字符并获取结果的最后一个元素：
line.split('_', 1)[-1]
This will also work for lines that do nothave an underscore character on the line.
这也适用于行上没有下划线字符的行。
Demo:
演示：
>>> 'Grp25_QTY47 5'.split('_', 1)[-1]
'QTY47 5'
>>> 'No underscore'.split('_', 1)[-1]
'No underscore'
Translating this to your code:
将其转换为您的代码：
import textwrap
ta_to = ta_from.copyta(status=endstatus)
with botslib.opendata(ta_from.filename,'r') as infile:
with botslib.opendata(str(ta_to.idta),'wb') as tofile:
for line in textwrap.wrap(next(infile), 640):
line = line.split('_', 1)[-1]
tofile.write(line + '\r\n')
