bash 如何在bash脚本中使用for循环复制和重命名文件？
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how to copy and rename file with for loop in bash script?
提问by user2467583
How I can copy all file *.html to *.php with For loop?
如何使用 For 循环将所有文件 *.html 复制到 *.php？
help me...
帮我...
this my script :
这是我的脚本：
#!/bin/bash
list="$(ls *.html)"
for i in "$list"
do
newname=$(ls "$i" | sed -e 's/html/php/')
cat beginfile > "$newname"
cat "$i" | sed -e '1,26d' | tac | sed -e '1,21d' | tac >> "$newname"
cat endfiel >> "$newname"
done
or you have another ide ?
或者你有另一个想法？
回答by Chris Dodd
for f in *.html; do cp $f ${f%.html}.php; done
回答by janos
Here you go:
干得好：
for i in *.html; do mv "$i" "${i%.html}.php"; done
In RedHat Linux and derivatives there is a renameutility that simplifies this to:
在 RedHat Linux 和衍生产品中，有一个rename实用程序可以将其简化为：
rename .html .php *.html
In Debian Linux and derivatives there is a renameutility that simplifies this to:
在 Debian Linux 和衍生产品中，有一个rename实用程序可以将其简化为：
rename 's/.html$/.php/' *.html
Check man renameor rename --helpto see how to use the implementation you have. Sometimes the utility is called rename.plinstead of simply rename.
检查man rename或rename --help以了解如何使用您拥有的实现。有时，实用程序被调用rename.pl而不是简单地调用rename。
回答by Reinstate Monica Please
Can omit the for loop altogeather if you have perl packages installed.
如果你安装了 perl 包，可以省略 for 循环。
#!/bin/bash
rename 's/html/php/' *.html
