bash 使用文件名列表填充和读取数组
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populate and read an array with a list of filenames
提问by Fabio B.
Trivial question.
琐碎的问题。
#!/bin/bash
if test -z ""
then
echo "No args!"
exit
fi
for newname in $(cat ); do
echo $newname
done
I want to replace that echo inside the loop with array populationcode. Then, after the loop ends, I want to read the arrayagain and echo the contents. Thanks.
我想用数组填充代码替换循环内的回声。然后，在循环结束后，我想再次读取数组并回显内容。谢谢。
回答by Diego Sevilla
If the file, as your code shows, has a set of files, each in one line, you can assign the value to the array as follows:
如果文件（如您的代码所示）有一组文件，每个文件在一行中，您可以将值分配给数组，如下所示：
array=(`cat `)
After that, to process every element you can do something like:
之后，要处理每个元素，您可以执行以下操作：
for i in ${array[@]} ; do echo "file = $i" ; done
回答by l0b0
declare -a files
while IFS= read -r
do
files+=("$REPLY") # Array append
done < ""
echo "${files[*]}" # Print entire array separated by spaces
catis not neededfor this.
cat不需要这个。
回答by Laimoncijus
#!/bin/bash
files=( )
for f in $(cat ); do
files[${#files[*]}]=$f
done
for f in ${files[@]}; do
echo "file = $f"
done
