如何在 bash shell 脚本中读取和拆分逗号分隔的文件？
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How to read and split comma separated file in a bash shell script?
提问by user3492304
I want to read a file line by line, split each line by comma (,) and store the result in an array. How to do this in a bash shell script?
我想逐行读取文件，用逗号 (,) 分割每一行并将结果存储在一个数组中。如何在 bash shell 脚本中执行此操作？
Sample line in my comma separated file
我的逗号分隔文件中的示例行
123,2014-07-21 10:01:44,123|8119|769.00||456|S
This should be the output after splitting:
这应该是拆分后的输出：
arr[0]=123 arr[1]=2014-07-21 10:01:44 arr[2]=123|8119|769.00||456|S
回答by konsolebox
Use read -ato split each line read into array based from IFS.
用于read -a将读取的每一行拆分为基于 IFS 的数组。
while IFS=, read -ra arr; do
## Do something with ${arr0]}, ${arr[1]} and ${arr[2]}
...
done < file
If the third field can also contain commas, you can prevent it from being split by using finite non-array parameters:
如果第三个字段也可以包含逗号，则可以通过使用有限的非数组参数来防止它被拆分：
while IFS=, read -r a b c; do
## Do something with $a, $b and $c
...
done < file
From help read:
来自help read：
Reads a single line from the standard input, or from file descriptor FD if the -u option is supplied. The line is split into fields as with word splitting, and the first word is assigned to the first NAME, the second word to the second NAME, and so on, with any leftover words assigned to the last NAME. Only the characters found in $IFS are recognized as word delimiters. -a array assign the words read to sequential indices of the array variable ARRAY, starting at zero
Reads a single line from the standard input, or from file descriptor FD if the -u option is supplied. The line is split into fields as with word splitting, and the first word is assigned to the first NAME, the second word to the second NAME, and so on, with any leftover words assigned to the last NAME. Only the characters found in $IFS are recognized as word delimiters. -a array assign the words read to sequential indices of the array variable ARRAY, starting at zero
