java 使用 Collections.sort 对自定义类数组列表字符串进行排序
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Sorting custom class array-list string using Collections.sort
提问by kaibuki
I am trying to sort my custom class array-list using Collections.sort by declaring my own anonymous comparator. But the sort is not working as expected.
我试图通过声明我自己的匿名比较器来使用 Collections.sort 对我的自定义类数组列表进行排序。但是排序没有按预期工作。
My code is
我的代码是
Collections.sort(arrlstContacts, new Comparator<Contacts>() {
public int compare(Contacts lhs, Contacts rhs) {
int result = lhs.Name.compareTo(rhs.Name);
if(result > 0)
{
return 1;
}
else if (result < 0)
{
return -1;
}
else
{
return 0;
}
}
});
The result is not in sorted order.
结果没有排序。
回答by Nick Holt
Like Adam says, simply do:
就像亚当说的，简单地做：
Collections.sort(
arrlstContacts,
new Comparator<Contacts>()
{
public int compare(Contacts lhs, Contacts rhs)
{
return lhs.Name.compareTo(rhs.Name);
}
}
);
The method String.compareToperforms a lexicographical comparison which your original code is negating. For example the strings number1and number123when compared would produce -2 and 2 respectively.
该方法String.compareTo执行您的原始代码否定的字典顺序比较。例如，字符串number1和number123when 比较将分别产生 -2 和 2。
By simply returning 1, 0 or -1 there's a chance (as is happening for you) that the merge part of the merge sort used Collections.sortmethod is unable to differentiate sufficiently between the strings in the list resulting in a list that isn't alphabetically sorted.
通过简单地返回 1、0 或 -1，有可能（正如您正在发生的那样）合并排序所用Collections.sort方法的合并部分无法充分区分列表中的字符串，从而导致列表未按字母顺序排序.
回答by Mark Pazon
As indicated by Adam, you can use return (lhs.Name.compareTo(rhs.Name));likeso:
正如 Adam 所指出的，您可以使用return (lhs.Name.compareTo(rhs.Name));likeso：
Collections.sort(arrlstContacts, new Comparator<Contacts>() {
public int compare(Contacts lhs, Contacts rhs) {
return (lhs.Name.compareTo(rhs.Name));
}
});
