javascript 如何检查物体的深度？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/13523951/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
How to check the depth of an object?
提问by Kavi Siegel
I'm working on a permissions system with variable depth; depending on the complexity of a page, there could be more or less levels. I searched StackOverflow to find if this has been asked before, couldn't find it.
我正在研究具有可变深度的权限系统；根据页面的复杂程度，可以有更多或更少的级别。我搜索了 StackOverflow 以查找之前是否有人问过这个问题，但找不到。
If I have this object:
如果我有这个对象：
{foo:{bar:{baz : 'baa'}}}
I need it to return 3, it has 3 levels to it.
我需要它返回 3，它有 3 个级别。
With this object:
有了这个对象：
{abc: 'xyz'}
It would have to be 1.
它必须是 1。
This is what I have so far:
这是我到目前为止：
utils.depthOf = function(object, level){
// Returns an int of the deepest level of an object
level = level || 1;
var key;
for(key in object){
if (!object.hasOwnProperty(key)) continue;
if(typeof object[key] == 'object'){
level++;
level = utils.depthOf(object[key], level);
}
}
return level;
}
The problem is it counts sister elements too. It's actually not getting depth, it's counting all members of an object.
问题是它也计算姐妹元素。它实际上并没有获得深度，而是在计算对象的所有成员。
回答by Kavi Siegel
Well, here you go buddy, a function that does exactly what you need!
好吧，伙计，你去吧，一个完全满足你需要的功能！
utils.depthOf = function(object) {
var level = 1;
for(var key in object) {
if (!object.hasOwnProperty(key)) continue;
if(typeof object[key] == 'object'){
var depth = utils.depthOf(object[key]) + 1;
level = Math.max(depth, level);
}
}
return level;
}
A lot easier than we thought it would be. The issue was how it was incremented, it shouldn't have been recursively adding, rather getting the bottom-most and adding one, then choosing the max between two siblings.
比我们想象的要容易得多。问题是它是如何递增的，它不应该递归添加，而是获取最底层并添加一个，然后在两个兄弟姐妹之间选择最大值。
回答by Yippee
We can use the reg:
我们可以使用 reg：
function getHowManyLevel(obj) {
let res = JSON.stringify(obj).replace(/[^{|^}]/g, '')
while (/}{/g.test(res)) {
res = res.replace(/}{/g, '')
}
return res.replace(/}/g, '').length
}回答by DonFuchs
This should do it, if you wanna keep it short:
如果你想保持简短，这应该可以：
function maxDepth(object) {
if (typeof object !== "object" || object === null) {
return 0;
}
let values = Object.values(object);
return (values.length && Math.max(...values.map(value => maxDepth(value)))) + 1;
}
