Python 仅从此元素中提取文本，而不是其子元素
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Only extracting text from this element, not its children
提问by Dragon
I want to extract only the text from the top-most element of my soup; however soup.text gives the text of all the child elements as well:
我只想从汤的最顶层元素中提取文本；然而，soup.text 也给出了所有子元素的文本：
I have
我有
import BeautifulSoup
soup=BeautifulSoup.BeautifulSoup('<html>yes<b>no</b></html>')
print soup.text
The output to this is yesno. I want simply 'yes'.
对此的输出是yesno. 我只想说“是”。
What's the best way of achieving this?
实现这一目标的最佳方法是什么？
Edit: I also want yesto be output when parsing '<html><b>no</b>yes</html>'.
编辑：我也想yes在解析' <html><b>no</b>yes</html>'时输出。
采纳答案by jbochi
what about .find(text=True)?
怎么样.find(text=True)？
>>> BeautifulSoup.BeautifulSOAP('<html>yes<b>no</b></html>').find(text=True)
u'yes'
>>> BeautifulSoup.BeautifulSOAP('<html><b>no</b>yes</html>').find(text=True)
u'no'
EDIT:
编辑：
I think that I've understood what you want now. Try this:
我想我已经明白你现在想要什么了。尝试这个：
>>> BeautifulSoup.BeautifulSOAP('<html><b>no</b>yes</html>').html.find(text=True, recursive=False)
u'yes'
>>> BeautifulSoup.BeautifulSOAP('<html>yes<b>no</b></html>').html.find(text=True, recursive=False)
u'yes'
回答by TigrisC
You could use contents
你可以使用内容
>>> print soup.html.contents[0]
yes
or to get all the texts under html, use findAll(text=True, recursive=False)
或者要获取 html 下的所有文本，请使用 findAll(text=True, recursive=False)
>>> soup = BeautifulSoup.BeautifulSOAP('<html>x<b>no</b>yes</html>')
>>> soup.html.findAll(text=True, recursive=False)
[u'x', u'yes']
above joined to form a single string
上面连接形成一个字符串
>>> ''.join(soup.html.findAll(text=True, recursive=False))
u'xyes'
回答by mzjn
You might want to look into lxml's soupparsermodule, which has support for XPath:
您可能需要查看 lxml 的soundparser模块，它支持 XPath：
>>> from lxml.html.soupparser import fromstring
>>> s1 = '<html>yes<b>no</b></html>'
>>> s2 = '<html><b>no</b>yes</html>'
>>> soup1 = fromstring(s1)
>>> soup2 = fromstring(s2)
>>> soup1.xpath("text()")
['yes']
>>> soup2.xpath("text()")
['yes']
回答by Horst Miller
This works for me in bs4:
这在 bs4 中对我有用：
import bs4
node = bs4.BeautifulSoup('<html><div>A<span>B</span>C</div></html>').find('div')
print "".join([t for t in node.contents if type(t)==bs4.element.NavigableString])
output:
输出：
AC
