C++ '*' 标记之前的预期构造函数、析构函数或类型转换
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Expected constructor, destructor, or type conversion before '*' token
提问by Freezerburn
I honestly have no idea why this is happening. I checked, double-checked, and triple-checked curly braces, semicolons, moved constructors around, etc. and it still gives me this error.
老实说，我不知道为什么会这样。我检查、双重检查和三重检查大括号、分号、移动构造函数等，它仍然给我这个错误。
Relevant code follows.
相关代码如下。
BinTree.h
二进制树
#ifndef _BINTREE_H
#define _BINTREE_H
class BinTree
{
private:
struct Node
{
float data;
Node *n[2];
};
Node *r;
Node* make( float );
public:
BinTree();
BinTree( float );
~BinTree();
void add( float );
void remove( float );
bool has( float );
Node* find( float );
};
#endif
And BinTree.cpp
和 BinTree.cpp
#include "BinTree.h"
BinTree::BinTree()
{
r = make( -1 );
}
Node* BinTree::make( float d )
{
Node* t = new Node;
t->data = d;
t->n[0] = NULL;
t->n[1] = NULL;
return t;
}
回答by Michael Burr
Because on the line:
因为上线了：
Node* BinTree::make( float d )
the type Nodeis a member of class BinTree.
类型Node是 的成员class BinTree。
Make it:
做了：
BinTree::Node* BinTree::make( float d )
