bash 比较两个文件并获得相同行的输出

compare two files and get the output for the same lines

提问by garconcn

How can I get the following output using linux command by comparing two text files? Thanks.

如何通过比较两个文本文件使用 linux 命令获得以下输出？谢谢。

file1:

文件 1：

site110
site120

file2(Updated):

文件 2（更新）：

domain1.com - site110
domain2.com - site111
domain3.com - site112
domain4.com - site113
domain5.com - site120
domain6.com - site1201
domain7.com - site1202

output:

输出：

domain1.com - site110
domain5.com - site120

If I use:

如果我使用：

grep -f file1 file2

the output will be:

输出将是：

domain1.com - site110
domain5.com - site120
domain6.com - site1201
domain7.com - site1202

which the last two lines are not what I want. Thanks.

最后两行不是我想要的。谢谢。

回答by ire_and_curses

From the grep manpage:

从grep 联机帮助页：

   -f FILE, --file=FILE
          Obtain  patterns  from  FILE,  one  per  line.   The  empty file
          contains zero patterns, and therefore matches nothing.   (-f  is
          specified by POSIX.)

Therefore:

所以：

grep -f file1 file2

domain1.com - site110
domain5.com - site120

回答by Antony.H

Use commcommand.

使用comm命令。

comm -12 < (sort file1) < (sort file2)

This command is more accurate than grep -f.

此命令比grep -f.

回答by jfg956

I think you are looking for a kind of database join function. Unix has a command for that: join. In you case:

我认为您正在寻找一种数据库连接功能。Unix 有一个命令：join。在你的情况下：

join -1 1 -2 3 -t " " -o 2.1,2.2,2.3 file1 file2

回答by modz0r

How about diff?

差异怎么样？

回答by osgx

May be man paste? Some output processing can be needed.

可能是man paste？可能需要一些输出处理。