Linux 你如何给 su 当前用户环境变量
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How do you give su the current user environment variables
提问by kenneth koontz
I have a variable that is set through .bashrc.
我有一个通过.bashrc.
In ~/.bashrc:
在~/.bashrc：
PROJ_HOME=~/Projects/stable
From a bash shell, I'd like to do something like this:
从 bash shell，我想做这样的事情：
$ su -l kenneth -c 'echo $PROJ_HOME'
However, when I do this, the expected /home/kenneth/Projects/stableis not printed out.
但是，当我这样做时，预期/home/kenneth/Projects/stable不会打印出来。
Any ideas on how I can do this?
关于我如何做到这一点的任何想法？
采纳答案by Paused until further notice.
You need to export the variable. You may not need to use the -moption to suto preserve the environment.
您需要导出变量。您可能不需要使用-m选项su来保护环境。
export PROJ_HOME=~/Projects/stable
回答by Carlo
Try with su -m -l kenneth -c 'echo $PROJ_HOME'. -m should preserve the environment.
尝试使用su -m -l kenneth -c 'echo $PROJ_HOME'. -m 应该保护环境。
EDIT
Reading your question one more time, I think I might understood it reversed.
You might also try this: su -l kenneth -c '. /home/kenneth/.bashrc; echo $PROJ_HOME.
编辑再读一遍你的问题，我想我可能理解它反过来了。你也可以试试这个：su -l kenneth -c '. /home/kenneth/.bashrc; echo $PROJ_HOME。
回答by Dan V
Have you tried the option su -m ?
您是否尝试过选项 su -m ？
-m, --preserve-environment
do not reset environment variables
For example: su -m kenneth -c 'echo $PROJ_HOME'
例如： su -m kenneth -c 'echo $PROJ_HOME'
回答by Earl Ruby
Use single quotes around the command:
在命令周围使用单引号：
$ su -l kenneth -c 'echo $PROJ_PATH'
Double quotes interprets the value of $PROJ_PATHas seen by root (empty string), then executes the command "echo (empty string)"as the user kenneth.
双引号解释$PROJ_PATHroot 看到的值（空字符串），然后"echo (empty string)"以用户 kenneth 的身份执行命令。
Single quotes will pass 'echo $PROJ_PATH'as the command, and the value of $PROJ_PATHin kenneth's environment is what will be echoed.
单引号将'echo $PROJ_PATH'作为命令传递，$PROJ_PATH在 kenneth 的环境中的值将被回显。
