bash 一个案例中有多个命令？
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Multiple commands in a case?
提问by dominique120
Is it possible to do this:
是否有可能做到这一点：
case $ans1_1 in
y)fedoraDeps;;
echo "something here";;
make -j 32;;
n)echo "Continuing"...;;
;;
*) echo "Answer 'y' or 'n'";;
esac
Where fedoraDepsis a function with yumcommands.
fedoraDeps带yum命令的函数在哪里。
I'm trying to replicate this with cases:
我试图用案例复制这一点：
if [[ $ans1_1 = y ]]; then
fedoraDeps
echo "something here"
make -j 32
elif [[ $ans1_1 = n ]]; then
echo "Continuing..."
:
else
echo "Answer 'y' or 'n'"
fi
回答by that other guy
;or line feed is used to end a command. ;;is used to end the case branch. Just don't try to end the case branch after every command, and it's fine:
;或换行用于结束命令。;;用于结束 case 分支。只是不要尝试在每个命令之后结束 case 分支，这很好：
case $ans1_1 in
y)
fedoraDeps
echo "something here"
make -j 32 ;;
n)
echo "Continuing"... ;;
*)
echo "Answer 'y' or 'n'" ;;
esac
回答by Dale_Reagan
Due to variations in shell behaviors I suggest using spaces before semicolons... Single ';' allow for what you want. Double ';' 'end' the case 'match', i.e.
由于 shell 行为的变化，我建议在分号前使用空格......单个 ';' 允许你想要什么。双倍的 ';' “结束”案例“匹配”，即
This should work:
这应该有效：
case $ans1_1
in
y) fedoraDeps ;
echo "something here" ;
make -j 32 ;; ## last command for case 'match'
n) echo "Continuing"... ;;
## if you want a blank line then just use one
*) echo "Answer 'y' or 'n'" ;;
esac
