bash 比较两个文件的行，打印第一个文件独有的行
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Compare lines of two files, print lines unique to first file
提问by Elliot Chance
I have two text files that contain a unique sorted list of words:
我有两个包含唯一排序单词列表的文本文件：
File 1:
文件 1：
a
b
c
d
File 2:
文件2：
b
c
I need a new file that contains only the extraneous lines in File 1, so the result will be
我需要一个仅包含文件 1 中无关行的新文件，因此结果将是
a
d
回答by kojiro
This is what commis for:
这comm是为了：
comm-- select or reject lines common to two files
comm-- 选择或拒绝两个文件共有的行
You want
你要
comm -23 "File 1" "File 2"
which will suppress output of lines only in file 2and lines in both files, leaving only lines in file 1.More answers here on Greg Wooledge's wiki
这将抑制产量仅在文件2号线和在这两个文件中的行，只留下行文件1.更多的答案对格雷格Wooledge的wiki在这里
回答by Rubens
You can use grep:
您可以使用grep：
grep -f file1.txt -vFx file2.txt
Notice the usage of the flags F, --fixed-stringsand x, --line-regexp, to force the comparison to be performed considering the entire line.
请注意标志F, --fixed-strings和x, --line-regexp,的用法，以强制在考虑整行的情况下执行比较。
回答by Alessandro
Try this
尝试这个
$ join file1.txt file2.txt -v 1
$ join file1.txt file2.txt -v 1
$ man join
$ man join
-a FILENUM
print unpairable lines coming from file FILENUM, where FILENUM is 1 or 2, corresponding to FILE1 or FILE2
-v FILENUM
like -a FILENUM, but suppress joined output lines
