解析错误：语法错误，第 3 行 C:\xampp\htdocs\yo\index.php 中的意外 T_STRING
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Parse error: syntax error, unexpected T_STRING in C:\xampp\htdocs\yo\index.php on line 3
提问by Deepak Kumar
I am new on php and i am trying to add this code
我是 php 新手，我正在尝试添加此代码
Im finding this error please any one who can solve this for me
我发现此错误，请任何可以为我解决此问题的人
<?php
$myName = ‘Guest';
$myVar = “Welcome back $myName”;
echo $myVar;
?>
This is my html
这是我的 html
<p><?php echo $myVar; ?></p>
Thanks
谢谢
回答by Fluffeh
Looks like you are using funny quotes rather than the straight ' and " types.
看起来您正在使用有趣的引号而不是直接的 ' 和 " 类型。
<?php
$myName = 'Guest';
$myVar = "Welcome back $myName";
echo $myVar;
?>
回答by mfadel
you need to write
你需要写
$myVar = "Welcome Back $myName";
the problem is that you are using the wrong char for the quote character
问题是您对引号字符使用了错误的字符
回答by sarojrana
<?php
$myName = "Guest";
$myVar = "Welcome back ".$myName;
echo $myVar;
?>
or
或者
<?php
$myName = "Guest";
$myVar = "Welcome back $myName";
echo $myVar;
?>
This is how code works while concatenating the string.
这就是连接字符串时代码的工作方式。
回答by manoj03h
Write $myVar = “Welcome back" . $myName;instead $myVar = “Welcome back $myName";
写$myVar = “Welcome back" . $myName;代替$myVar = “Welcome back $myName";
<?php
$myName = ‘Guest';
$myVar = “Welcome back" . $myName;
echo $myVar;
?>
