spring 找不到url Observer的请求
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Can't find the request for url Observer
提问by Ananth Duari
I am working with sample REST service with Apache CXF, But somehow I am not able to call the service. My implementation class is,
我正在使用 Apache CXF 使用示例 REST 服务，但不知何故我无法调用该服务。我的实现类是，
package com.ananth.lab.cfxrest.service;
import com.ananth.lab.cfxrest.vo.Address;
import com.ananth.lab.cfxrest.vo.Employee;
import org.springframework.stereotype.Service;
import javax.jws.WebService;
import javax.ws.rs.*;
import java.util.ArrayList;
import java.util.Collection;
import java.util.List;
@Path("/cservice")
@Produces("application/xml")
public class EmployeeService {
@GET
@Path("/emp")
public Employee getEmployee() {
Address address1 = new Address();
address1.setCity("Chennai");
address1.setZip(63);
List<Address> list = new ArrayList<Address>();
Address address2 = new Address();
address2.setCity("Bangalore");
address2.setZip(49);
list.add(address1);
list.add(address2);
Employee emp = new Employee();
emp.setAddress(list);
emp.setEmployeeId("001");
emp.setEmployeeName("Ananth");
return emp;
}
}
My web.xml file is,
我的 web.xml 文件是，
<!DOCTYPE web-app PUBLIC
"-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd" >
<web-app>
<display-name>Hello world REST service with apache cxf</display-name>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>WEB-INF/beans.xml,WEB-INF/applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<servlet>
<servlet-name>CXFServlet</servlet-name>
<display-name>CXF Servlet</display-name>
<servlet-class>
org.apache.cxf.transport.servlet.CXFServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>CXFServlet</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
</web-app>
I deployed in Tomcat and the context path is "Lab". So I am trying to access the service like:
我部署在Tomcat中，上下文路径是“Lab”。所以我试图访问该服务，如：
http://localhost:8080/Lab/cservice/emp
I am getting
我正进入（状态
No service was found.
采纳答案by supergaosong
I think you should make sure that your Employee class have a correctly "@" remark. just like below:
我认为你应该确保你的 Employee 类有一个正确的“@”注释。就像下面一样：
@XmlRootElement(name="cservice")
public class Employee (){
private String employeeId;
private String employeeName;
...
@XmlElement(name="employeeId")
public void setEmployeeId(String employeeId){
...
}
public String getEmployeeId(){
return this.employeeId;
}
@XmlElement(name="employeeName")
public void setEmployeeName(String employeeId){
...
}
public String getEmployeeName(){
return this.employeeName
}
...
...
}
and I suggest you to check WEB-INF/beans.xml & WEB-INF/applicationContext.xml.
我建议您检查 WEB-INF/beans.xml 和 WEB-INF/applicationContext.xml。
回答by Mengyu ZHang
Make sure your request url endpoint match your server endpoint.
确保您的请求 url 端点与您的服务器端点匹配。
combine url in web.xml and beans.xml result your endpoint
在 web.xml 和 beans.xml 中结合 url 结果你的端点
