bin bash 糟糕的解释器
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时间：2020-09-18 11:12:55 来源:igfitidea点击:
bin bash bad interpreter
提问by Stipe Viskov
#! bin/bash
mkdir ~/folder
while [ $brojac -le 5]
do
mkdir ~/folder/zad"$brojac"
brojac = $(( brojac+1 ))
done
this is my shellscript,but when I want to run it in terminal, I receive this error
这是我的 shellscript，但是当我想在终端中运行它时，我收到此错误
mint@mint ~ $ ./prvi.sh
bash: ./prvi.sh: bin/bash: bad interpreter: No such file or directory
mint@mint ~ $
采纳答案by Beggarman
Small errors in your script:
脚本中的小错误：
- $brojac is unassigned, so your integer comparison fails. Assign it an initial value to fix.
- '[' calls test, so you need spaces around opening and closing braces.
- You can't have spaces around your equal sign when assigning a value.
- $brojac 未分配，因此您的整数比较失败。为其分配一个初始值以进行修复。
- '[' 调用 test，因此您需要在左括号和右括号周围留出空格。
- 分配值时，等号周围不能有空格。
Your script, updated:
您的脚本已更新：
#!/bin/bash
mkdir ~/folder
brojac=0
while [ $brojac -le 5 ]
do
mkdir ~/folder/zad"$brojac"
brojac=$(( brojac+1 ))
done
回答by Eugene
It should be
它应该是
#!/bin/bash
(first slash)
（第一个斜线）
回答by glenn Hymanman
#!/bin/bash
mkdir ~/folder
brojac=0
while [ "$brojac" -le 5 ] # with [...], need to quote vars and spaces around [ and ]
do
mkdir ~/folder/zad"$brojac"
brojac=$(( brojac+1 )) # cannot have spaces around =
done
I would write:
我会写：
for ((i=0; i<=5, i++)); do
mkdir -p ~/folder/zad$i
done
回答by jm666
Or with an simple
或者用一个简单的
mkdir -p ~/folder/zad{1..5}
if you want zad1, zad2 .. zad5
如果你想 zad1, zad2 .. zad5
or
或者
mkdir -p ~/folder/zad{,1..5}
if you want zad, zad1, zad2 .. zad5
如果你想 zad, zad1, zad2 .. zad5
