javascript val.replace(/[^a-zA-Z_-0-9]/g, '') 产生语法错误：字符类中的范围无效
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val.replace(/[^a-zA-Z_-0-9]/g, '') produce SyntaxError: invalid range in character class
提问by Oleksandr IY
I need to replace all chars which are not match with range a-zA-Z_-0-9. So I do val.replace(/[^a-zA-Z_-0-9]/g, '')but get error. How can I bit this?
Thanks
我需要替换所有与 range 不匹配的字符a-zA-Z_-0-9。所以我做val.replace(/[^a-zA-Z_-0-9]/g, '')但得到错误。我怎么能咬这个？谢谢
回答by Dmitry
If you want to include the minus sign "-" in the character class, you have to put it into the end of range:
如果要在字符类中包含减号“-”，则必须将其放入范围末尾：
val.replace(/[^a-zA-Z_0-9-]/g, '')
回答by sQVe
I would prefer this regex:
我更喜欢这个正则表达式：
val.replace(/[^\w-]+/gi, "");
回答by Simon Richter
回答by pimvdb
You expect that -character to be parsed as being literal, but it is in fact parsed as a range: _-0means _to 0, just like a-zmeans ato z. However, since _has a higher character code than 0, you get an error.
您希望该-字符被解析为文字，但实际上它被解析为一个范围：_-0表示_to 0，就像a-z表示ato 一样z。但是，由于_字符代码高于0，您会收到错误消息。
In your case, just escape it: \-. This is parsed as the -character.
在您的情况下，只需将其转义即可：\-. 这被解析为-字符。
回答by Nicholas Albion
You need to escape the "-"
你需要逃避“-”
val.replace(/[^a-zA-Z_\-0-9]/g, '')
回答by Birei
You have a bad range, remove the -between _and the number range and put it at the end or at the beginning.
你有一个错误的范围，删除-之间_和数字范围并将其放在末尾或开头。
回答by Dariush Jafari
try this:
试试这个：
val.replace(/[^a-zA-Z_0-9-]/g, '');
回答by edgar berumen
$(this).val($(this).val().replace(/[^a-zA-Z_0-9-]/g, ''));
