pandas 将熊猫日期时间索引向前一天设置
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Set pandas datetime index one day forward
提问by Uninvited
Is it possible to set one day forward a datetime index in pandas?
是否可以在 Pandas 中设置一个日期时间索引？
I've got this index
我有这个索引
mydata.data.index
Out[7]: <class 'pandas.tseries.index.DatetimeIndex'>
[2013-01-27 22:00:00, ..., 2014-12-16 22:00:00]
Length: 500, Freq: None, Timezone: None
and its wrong. The correct date that the data begin is the day after. That is 2014-12-17 and they end at 2013-01-28
它是错误的。数据开始的正确日期是后一天。那是 2014-12-17，它们在 2013-01-28 结束
Is there a way to fix this?
有没有办法来解决这个问题？
回答by joris
Some different options:
一些不同的选择：
Use the shiftmethod:
使用shift方法：
In [10]: dti = pd.date_range('2012-01-01', periods=2)
In [11]: dti
Out[11]:
<class 'pandas.tseries.index.DatetimeIndex'>
[2012-01-01, 2012-01-02]
Length: 2, Freq: D, Timezone: None
In [13]: dti.shift(1, freq='D')
Out[13]:
<class 'pandas.tseries.index.DatetimeIndex'>
[2012-01-02, 2012-01-03]
Length: 2, Freq: D, Timezone: None
But maybe more easy (as @Evert notices), you can simply add a timedelta of one day:
但也许更容易（正如@Evert 所通知的那样），您可以简单地添加一天的时间增量：
In [14]: dti + pd.Timedelta('1 day')
Out[14]:
<class 'pandas.tseries.index.DatetimeIndex'>
[2012-01-02, 2012-01-03]
Length: 2, Freq: None, Timezone: None
For older pandas versions, you can also just use datetime.timedelta(days=1)(pd.Timedeltais only avaible starting from 0.15).
对于较旧的 Pandas 版本，您也可以使用datetime.timedelta(days=1)(pd.Timedelta仅从 0.15 开始可用)。
