pandas 求min和max等函数，pandas系列
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Finding min and max and other functions, pandas series
提问by user3659451
Let ssbe a pandas series of floats.
让我们ss成为一个Pandas系列的花车。
Let xbe a float.
让我们x成为一个浮动。
x+1and ss+1work as expected.
x+1并按ss+1预期工作。
x/5and ss/5work as expected.
x/5并按ss/5预期工作。
However min(x,5)works, but in order to get the same behavior with the series I must do ss.apply(lambda y: min(y,6))and this is a pain for the following reason:
但是min(x,5)有效，但为了获得与该系列相同的行为，我必须这样做ss.apply(lambda y: min(y,6))，由于以下原因，这很痛苦：
What if I want to do a batch of calculations on a series, and then as new elements appear, I want to do on the fly calculations?
如果我想对一个系列进行一批计算，然后当新元素出现时，我想进行动态计算怎么办？
In other words I'd like a function fso that I can apply fto a series (or multiple series) as well as applying fto a float (or multiple floats), and ideally apply fto a combination of floats and series.
换句话说，我想要一个函数，f以便我可以应用于f一个系列（或多个系列）以及应用于f一个浮点数（或多个浮点数），并且理想地适用f于浮点数和系列的组合。
I care about this because there may be many such transformations and I would highly prefer not maintaining two different versions of each transformation, one for batches and one for instant one-offs.
我关心这一点，因为可能有很多这样的转换，我非常不想为每个转换维护两个不同的版本，一个用于批量，一个用于即时一次性。
回答by orange
If you have a scalar, you can either convert it to a Series and work on the Series
如果您有标量，则可以将其转换为系列并处理系列
import pandas as pd
s = pd.Series(range(10, 20))
print s.min()
f = 6
print s.append(pd.Series([f])).min()
or convert the Series to a scalar value and use the normal min()function
或将系列转换为标量值并使用普通min()函数
print min(s.min(), f)
