java 如何将此日期格式与正则表达式匹配？
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How to match this date format with a regex?
提问by MarkJ
hi to all regex master out there, I know you have a work around with regards to my problem. hehe
向所有正则表达式大师致敬，我知道您可以解决我的问题。呵呵
02-May-2011
or
或者
22-May-2011
or
或者
2-May-2011
(dd-MMM-yyyy) with yyyy not accepting any other characters than digit
(dd-MMM-yyyy) yyyy 不接受除数字以外的任何其他字符
回答by Town
[0-9]{1,2}/[a-zA-Z]{3}/[0-9]{4}
That's assuming that the month is a 3-letter version: eg, Jan, Feb, Mar.
假设月份是 3 个字母的版本：例如，Jan、Feb、Mar。
Updated version to match the changes to the question:
更新版本以匹配对问题的更改：
[0-9]{1,2}-[a-zA-Z]{3}-[0-9]{4}
As has been mentioned, this won't actually validate the date, it'll just validate that the string matches the format of: 1 or 2 numbers, a dash, 3 letters, a dash, 4 numbers.
如前所述，这实际上不会验证日期，它只会验证字符串是否与以下格式匹配：1 或 2 个数字、一个破折号、3 个字母、一个破折号、4 个数字。
回答by Ry-
^\d{1,2}/[a-zA-Z]+/\d{4}$
Is probably what you're looking for. Although the technically correct one is:
大概就是你要找的。虽然技术上正确的是：
/^([12]\d|3[01])/(Jan(uary)?|Feb(ruary)?|Mar(ch)?|Apr(il)?|May|June?|July?|Aug(ust)?|Sep(t(ember)?)?|Oct(ober)?|Nov(ember)?|Dec(ember)?)/\d{4}$/i
Sorry for not validating February and the number of days in a month, but there are some things just not worth doing in regular expressions ;)
很抱歉没有验证二月和一个月的天数，但有些事情在正则表达式中不值得做;)
回答by Bhushan
Use SimpleDateFormat instead of using regexp. Read the tutorial at http://download.oracle.com/javase/tutorial/i18n/format/simpleDateFormat.htmlfor more info.
使用 SimpleDateFormat 而不是使用正则表达式。阅读http://download.oracle.com/javase/tutorial/i18n/format/simpleDateFormat.html 上的教程了解更多信息。
回答by S34N
/**
* Created with IntelliJ IDEA.
* User: S34N
* Date: 2013/07/30
* Time: 8:21 AM
* To change this template use File | Settings | File Templates.
*/
//Import the required classes/packages
import javax.swing.*;
import java.text.DateFormat;
import java.text.SimpleDateFormat;
import java.util.Date;
public class dateInputScan {
public static void main(String args[]) {
dateInputScan run = new dateInputScan();
run.dateInputScan();
}
public void dateInputScan() {
//Instantiating variables
String lvarStrDateOfTransaction = null;
DateFormat formatter = null;
Date lvarObjDateOfTransaction = null;
//Use one of the following date formats.
lvarStrDateOfTransaction = "29/07/2013";
//lvarStrDateOfTransaction = "29-07-2013";
//lvarStrDateOfTransaction = "20130729";
//lvarStrDateOfTransaction = "2013-07-29";
//lvarStrDateOfTransaction = "29/07/2013";
//You can also add your own regex (Regular Expression)
if (lvarStrDateOfTransaction.matches("([0-9]{2})/([0-9]{2})/([0-9]{4})")) {
formatter = new SimpleDateFormat("dd/MM/yyyy");
} else if (lvarStrDateOfTransaction.matches("([0-9]{2})-([0-9]{2})-([0-9]{4})")) {
formatter = new SimpleDateFormat("dd-MM-yyyy");
} else if (lvarStrDateOfTransaction.matches("([0-9]{4})([0-9]{2})([0-9]{2})")) {
formatter = new SimpleDateFormat("yyyyMMdd");
} else if (lvarStrDateOfTransaction.matches("([0-9]{4})-([0-9]{2})-([0-9]{2})")) {
formatter = new SimpleDateFormat("yyyy-MM-dd");
} else if (lvarStrDateOfTransaction.matches("([0-9]{4})/([0-9]{2})/([0-9]{2})")) {
formatter = new SimpleDateFormat("yyyy/MM/dd");
}
try {
lvarObjDateOfTransaction = formatter.parse(lvarStrDateOfTransaction);
JOptionPane.showMessageDialog(null, "Date: " + lvarObjDateOfTransaction);
} catch (Exception ex) { //Catch the Exception in case the format is not found.
JOptionPane.showMessageDialog(null, ex);
}
}
}
回答by Vladimir Stazhilov
Okay, here are almost all possible regex variations of the Date pattern:
好的，这里是日期模式的几乎所有可能的正则表达式变体：
private final static Pattern DATE_PATTERN_1 =
Pattern.compile (
"(?:Sun|Mon|Tue|Wed|Thu|Fri|Sat) " +
"(?:Jan|Feb|Mar|Apr|May|June?|July?|Aug|Sept?|Oct|Nov|Dec) " +
"\d\d \d\d:\d\d:\d\d \S+ \d\d\d\d", Pattern.CASE_INSENSITIVE);
private final static Pattern DATE_PATTERN_2 =
Pattern.compile (
"\d{4}.\d{2}.\d{2}", Pattern.CASE_INSENSITIVE);
private final static Pattern DATE_PATTERN_3 =
Pattern.compile (
"\d{2}.\d{2}.\d{4}", Pattern.CASE_INSENSITIVE);
private final static Pattern DATE_PATTERN_4 =
Pattern.compile (
"([0-9]{4})([0-9]{2})([0-9]{2})", Pattern.CASE_INSENSITIVE);
private final static Pattern DATE_PATTERN_5 =
Pattern.compile (
"^([12]\d|3[01]).(Jan(uary)?|Feb(ruary)?|Mar(ch)?|Apr(il)?|May|June?|July?|Aug(ust)?|Sep(t(ember)?)?|Oct(ober)?|Nov(ember)?|Dec(ember)?).\d{4})$", Pattern.CASE_INSENSITIVE);
Please note that "." character stand for any char.
请注意“。” 字符代表任何字符。
回答by Mukesh K
Since it is date, which you are trying to find a match, using SimpleDateFormat instead of a regex based match check should be the appropriate solution. Hopefully, the below snippet should do the job.
由于它是日期，您正在尝试查找匹配项，因此使用 SimpleDateFormat 而不是基于正则表达式的匹配检查应该是合适的解决方案。希望下面的代码片段可以完成这项工作。
public static boolean dateFormatValidate(String strDate,String dateFormat)
{
SimpleDateFormat formatter = new SimpleDateFormat(dateFormat);
String strParsed = null;
Date parsed =null;
try
{
parsed = formatter.parse(strDate);
strParsed = formatter.format(parsed);
}
catch (ParseException e)
{
MYLogger.logger.info(e.getMessage());
}
return strDate.equals(strParsed);
}
