ios 在 Swift 中对 NSDictionary 对象的 NSArray 进行排序
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Sort NSArray of NSDictionary objects in Swift
提问by jopeek
I have retrieved some JSON data from an API and now have an NSArray full of NSDictionary objects. Each NSDictionary has a key/value pair of "name" and I want to sort the NSArray by that key/value pair.
我已经从 API 中检索到了一些 JSON 数据，现在有了一个充满 NSDictionary 对象的 NSArray。每个 NSDictionary 都有一个“名称”键/值对，我想按该键/值对对 NSArray 进行排序。
I've done quite a bit of searching but none of the solutions I've come across seem to work in the new Swift language and I'm not sure if it's possibly a bug or not...
我已经做了很多搜索，但我遇到的所有解决方案似乎都不适用于新的 Swift 语言，我不确定它是否可能是一个错误......
I've tried:
我试过了：
var descriptor: NSSortDescriptor = NSSortDescriptor(key: "name", ascending: true)
var sortedResults: NSArray = results.sortedArrayUsingDescriptors(NSSortDescriptor(key: "name", ascending: true))
But that won't compile stating "NSSortDescriptor is not convertible to [AnyObject]".
但这不会编译说明“NSSortDescriptor 不可转换为 [AnyObject]”。
Any advice?
有什么建议吗？
回答by kambala
you must pass an array of sort descriptors (even if it's only one):
您必须传递一组排序描述符（即使它只有一个）：
var descriptor: NSSortDescriptor = NSSortDescriptor(key: "name", ascending: true)
var sortedResults: NSArray = results.sortedArrayUsingDescriptors([descriptor])
回答by ColinE
Rather than doing this the old way, why not embrace the new? The swift Array type has both sortand sortedmethods. You can supply a closure as the sort function:
与其以旧方式这样做，为什么不拥抱新方式呢？swift Array 类型同时具有sort和sorted方法。您可以提供一个闭包作为排序函数：
var sortedResults= results.sorted {
(dictOne, dictTwo) -> Bool in
// put your comparison logic here
return dictOne["name"]! > dictTwo["name"]!
}
回答by Ankit Goyal
var arrDescriptor = NSSortDescriptor(key: "", ascending: true)
var sortDescriptors: NSArray = [arrDescriptor]
_sortedArray = allKeysArray.sortedArrayUsingDescriptors(sortDescriptors as [AnyObject])
print(_sortedArray)
