Linux 正则表达式替换每行中最后一次出现的字符串
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Regex to replace last occurrence of a string in each line
提问by Michael
I am using sed -e 's/\(.*\)ABC/\1DEF/' myfileto replace the last occurrence of ABCwith DEFin a file.
我sed -e 's/\(.*\)ABC/\1DEF/' myfile用来替换文件中最后一次出现的ABCwith DEF。
I want to modify it to replace the last occurrence of ABCwith DEFin each linein the file.
我想修改它以替换文件中每一行中最后一次出现的ABCwith 。DEF
Is it possible to do with regex ?
是否可以使用正则表达式？
Thanks
谢谢
采纳答案by Bacon
You need to add 'g' to the end of your sed:
您需要在 sed 的末尾添加“g”：
sed -e 's/\(.*\)ABC/DEF/g'
This tells sed to replace every occurrence of your regex ("globally") instead of only the first occurrence.
这告诉 sed 替换每次出现的正则表达式（“全局”）而不是仅第一次出现。
EDIT:You should also add a $, if you want to ensure that it is replacing the last occurrence of ABC on the line:
编辑：$如果您想确保它替换行上最后一次出现的 ABC，您还应该添加一个:
sed -e 's/\(.*\)ABC$/DEF/g'
