Javascript jQuery 标签“for”属性选择器
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jQuery label 'for' attribute selector
提问by Jimmy Joyce
I am using Remy Sharp's labelover plugin for jQueryand I would like to exclude a label with the attribute forand value nature.
我正在为 jQuery使用 Remy Sharp 的labelover 插件，我想排除一个带有属性for和值的标签nature。
Here's an example of the code working:
这是代码工作的示例：
$(document).ready(function() {
$('form.default label').labelOver('over');
});
and what I'm trying to do:
以及我正在尝试做的事情：
$(document).ready(function() {
$('form.default label').not($('label').attr('for','nature')).labelOver('over');
});
Can anyone see where I'm going wrong? Feels like I'm pretty close to what I need to do.
谁能看到我哪里出错了？感觉我已经非常接近我需要做的事情了。
回答by Meligy
attris not a selector, it's a function that gets the attribute value with attribute name as the 1st argument, or sets it with a new value if one is passed as a 2ng argument.
attr不是选择器，它是一个函数，它以属性名称作为第一个参数获取属性值，或者如果一个新值作为 2ng 参数传递，则将其设置为新值。
Also, you excluded labels after selecting them with your notcall, because the selector labelmatched all labels, and attras I said did not filter that.
此外，您在通过not呼叫选择label标签后排除了标签，因为选择器匹配所有标签，并且attr正如我所说的那样没有过滤。
To select based on attribute, use this:
要根据属性进行选择，请使用以下命令：
$(document).ready(function() {
$("form.default label[for!='nature']").labelOver('over');
});
As you may have guessed, the [attribute='value']is the selector for an attribute "equal" to some value, and [attribute!='value']is the "not equal" version of it.
您可能已经猜到，the[attribute='value']是属性“等于”某个值的选择器，[attribute!='value']是它的“不等于”版本。
For reference see:
http://api.jquery.com/attribute-not-equal-selector/
参考：http:
//api.jquery.com/attribute-not-equal-selector/
For reference on all selectors:
http://api.jquery.com/category/selectors/
有关所有选择器的参考：http:
//api.jquery.com/category/selectors/
This is also referenced at my JavaScript & Web Dev Newsletter site.
回答by mak
.attr('for', 'nature')is setting the value for the forattribute to nature
.attr('for', 'nature')正在将for属性值设置为nature
To filter by attributes, use [attribute="value"]:
要按属性过滤，请使用[attribute="value"]：
$('form.default label').not('[for="nature"]').labelOver('over')
回答by Jacek Kaniuk
working code: http://jsfiddle.net/3nQbr/1/
工作代码：http: //jsfiddle.net/3nQbr/1/
$('label').not('[for="nature"]').labelOver('over');
