C++ 必须调用非静态成员函数的引用
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Reference to non-static member function must be called
提问by JavaRunner
I'm using C++ (not C++11). I need to make a pointer to a function inside a class. I try to do following:
我使用的是 C++（不是 C++11）。我需要创建一个指向类中函数的指针。我尝试执行以下操作：
void MyClass::buttonClickedEvent( int buttonId ) {
// I need to have an access to all members of MyClass's class
}
void MyClass::setEvent() {
void ( *func ) ( int );
func = buttonClickedEvent; // <-- Reference to non static member function must be called
}
setEvent();
But there's an error: "Reference to non static member function must be called". What should I do to make a pointer to a member of MyClass?
但是有一个错误：“必须调用对非静态成员函数的引用”。我应该怎么做才能指向 MyClass 的成员？
回答by imreal
The problem is that buttonClickedEventis a member function and you need a pointer to member in order to invoke it.
问题是这buttonClickedEvent是一个成员函数，您需要一个指向成员的指针才能调用它。
Try this:
尝试这个：
void (MyClass::*func)(int);
func = &MyClass::buttonClickedEvent;
And then when you invoke it, you need an object of type MyClassto do so, for example this:
然后当你调用它时，你需要一个类型的对象MyClass来这样做，例如this：
(this->*func)(<argument>);
http://www.codeguru.com/cpp/cpp/article.php/c17401/C-Tutorial-PointertoMember-Function.htm
http://www.codeguru.com/cpp/cpp/article.php/c17401/C-Tutorial-PointertoMember-Function.htm
回答by xiaodong
You may want to have a look at https://isocpp.org/wiki/faq/pointers-to-members#fnptr-vs-memfnptr-types, especially [33.1] Is the type of "pointer-to-member-function" different from "pointer-to-function"?
您可能想看看https://isocpp.org/wiki/faq/pointers-to-members#fnptr-vs-memfnptr-types，尤其是[33.1] 是“指向成员函数的指针”的类型“与“函数指针”不同？
