使用 PHP foreach 解析 JSON 数组
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Parsing JSON array with PHP foreach
提问by ToddN
Wondering why my PHP code will not display all "Value" of "Values" in the JSON data:
想知道为什么我的 PHP 代码不会在 JSON 数据中显示“值”的所有“值”：
$user = json_decode(file_get_contents($analytics));
foreach($user->data as $mydata)
{
echo $mydata->name . "\n";
}
foreach($user->data->values as $values)
{
echo $values->value . "\n";
}
The first foreach works fine, but the second throws an error.
第一个 foreach 工作正常，但第二个会引发错误。
{
"data": [
{
"id": "MY_ID/insights/page_views_login_unique/day",
"name": "page_views_login_unique",
"period": "day",
"values": [
{
"value": 1,
"end_time": "2012-05-01T07:00:00+0000"
},
{
"value": 6,
"end_time": "2012-05-02T07:00:00+0000"
},
{
"value": 5,
"end_time": "2012-05-03T07:00:00+0000"
}, ...
回答by Jonas Osburg
You maybe wanted to do the following:
您可能想要执行以下操作：
foreach($user->data as $mydata)
{
echo $mydata->name . "\n";
foreach($mydata->values as $values)
{
echo $values->value . "\n";
}
}
回答by Jonathan M
You need to tell it which index in datato use, or double loop through all.
您需要告诉它使用哪个索引data，或者双循环遍历所有索引。
E.g., to get the values in the 4th index in the outside array.:
例如，要获取外部数组中第 4 个索引中的值。：
foreach($user->data[3]->values as $values)
{
echo $values->value . "\n";
}
To go through all:
要通过所有：
foreach($user->data as $mydata)
{
foreach($mydata->values as $values) {
echo $values->value . "\n";
}
}
回答by Rocket Hazmat
$user->datais an array of objects. Each element in the array has a nameand valueproperty (as well as others).
$user->data是一个对象数组。数组中的每个元素都有一个nameandvalue属性（以及其他）。
Try putting the 2nd foreachinside the 1st.
尝试将第二个foreach放在第一个中。
foreach($user->data as $mydata)
{
echo $mydata->name . "\n";
foreach($mydata->values as $values)
{
echo $values->value . "\n";
}
}
