python：获取没有小数位的数字
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python: get number without decimal places
提问by l--''''''---------''''''''''''
a=123.45324
is there a function that will return just 123?
是否有一个函数只会返回123？
采纳答案by Mark Rushakoff
intwill always truncate towards zero:
int将始终向零截断：
>>> a = 123.456
>>> int(a)
123
>>> a = 0.9999
>>> int(a)
0
>>> int(-1.5)
-1
The difference between intand math.flooris that math.floorreturns the number as a float, and does not truncate towards zero.
之间的差int和math.floor是math.floor返回为浮点数的数量，并且不向零截断。
回答by Katriel
Python 2.x:
Python 2.x：
import math
int( math.floor( a ) )
N.B. Due to complicated reasons involving the handling of floats, the intcast is safe.
NB 由于涉及浮子处理的复杂原因，int演员是安全的。
Python 3.x:
Python 3.x：
import math
math.floor( a )
回答by Artur Gaspar
a = 123.45324
int(a)
回答by Avi Vajpeyi
If you want both the decimal and non-decimal part:
如果你想要小数和非小数部分：
def split_at_decimal(num):
integer, decimal = (int(i) for i in str(num).split("."))
return integer, decimal
And then:
进而：
>>> split_at_decimal(num=5.55)
(5, 55)
