python 调整目录中的图像大小
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Resize images in directory
提问by RailsSon
I have a directory full of images that I would like to resize to around 60% of their original size.
我有一个充满图像的目录，我想将其调整为原始大小的 60% 左右。
How would I go about doing this? Can be in either Python or Perl
我该怎么做呢？可以使用 Python 或 Perl
Cheers
干杯
Eef
埃夫
回答by Anurag Uniyal
If you want to do it programatically, which I assume is the case, use PIL to resize e.g.
如果您想以编程方式执行此操作，我认为是这种情况，请使用 PIL 调整大小，例如
newIm = im.resize((newW, newH)
then save it to same file or a new location.
然后将其保存到同一文件或新位置。
Go through the folder recursively and apply resize function to all images.
递归遍历文件夹并将调整大小功能应用于所有图像。
I have come up with a sample script which I think will work for you. You can improve on it: Maybe make it graphical, add more options e.g. same extension or may be all png, resize sampling linear/bilinear etc
我想出了一个我认为对你有用的示例脚本。你可以改进它：也许使它图形化，添加更多选项，例如相同的扩展名，或者可能都是 png，调整采样线性/双线性等
import os
import sys
from PIL import Image
def resize(folder, fileName, factor):
filePath = os.path.join(folder, fileName)
im = Image.open(filePath)
w, h = im.size
newIm = im.resize((int(w*factor), int(h*factor)))
# i am saving a copy, you can overrider orginal, or save to other folder
newIm.save(filePath+"copy.png")
def bulkResize(imageFolder, factor):
imgExts = ["png", "bmp", "jpg"]
for path, dirs, files in os.walk(imageFolder):
for fileName in files:
ext = fileName[-3:].lower()
if ext not in imgExts:
continue
resize(path, fileName, factor)
if __name__ == "__main__":
imageFolder=sys.argv[1] # first arg is path to image folder
resizeFactor=float(sys.argv[2])/100.0# 2nd is resize in %
bulkResize(imageFolder, resizeFactor)
回答by mirod
How about using mogrify, part of ImageMagick? If you really need to control this from Perl, then you could use Image::Magick, Image::Resizeor Imager.
如何使用 Mogrify，ImageMagick 的一部分？如果你真的需要从 Perl 控制它，那么你可以使用Image::Magick、Image::Resize或Imager。
回答by mirod
Can it be in shell?
它可以在外壳中吗？
mkdir resized
for a in *.jpg; do convert "$a" -resize 60% resized/"$a"; done
If you have > 1 core, you can do it like this:
如果你有 > 1 个内核，你可以这样做：
find . -maxdepth 1 -type f -name '*.jpg' -print0 | xargs -0 -P3 -I XXX convert XXX -resize 60% resized/XXX
-P3 means that you want to resize up to 3 images at the same time (parallelization).
-P3 意味着您要同时调整最多 3 个图像的大小（并行化）。
If you don't need to keep originals you can use mogrify, but I prefer to use convert, and then rm ...; mv ... - just to be on safe side if resizing would (for whatever reason) fail.
如果你不需要保留原件，你可以使用 mogrify，但我更喜欢使用 convert，然后 rm ...; mv ... - 只是为了安全起见，如果调整大小会（无论出于何种原因）失败。
回答by UncleZeiv
Use PerlMagick, it's an interface to the popular ImageMagicksuite of command line tools to do just this kind of stuff. PythonMagicis available as well.
使用PerlMagick，它是流行的ImageMagick命令行工具套件的接口，可以执行此类操作。PythonMagic也可用。
回答by Micha? Niklas
I use Python with PIL (Python Image Library). Of course there are specialized programs to do this.
我将 Python 与 PIL（Python 图像库）一起使用。当然，有专门的程序可以做到这一点。
Many people use PIL to such things. Look at: Quick image resizing with python
许多人使用 PIL 来做这样的事情。看：使用python快速调整图像大小
PIL is very powerful and recently I have found this recipe: Putting watermark to images in batch
PIL 非常强大，最近我发现了这个秘诀： 批量给图像添加水印
回答by Ganesh R.
do you need to just resize it or you want to resize programmatically? If just resize use PixResizer. http://bluefive.pair.com/pixresizer.htm
您需要调整它的大小还是想以编程方式调整大小？如果只是调整大小，请使用 PixResizer。http://bluefive.pair.com/pixresizer.htm
