javascript 在javascript中掷骰子
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Dice roll in javascript
提问by Elton Frederik
function rolldice() {
var x = Math.floor(Math.random() * ((6 - 1) + 1) + 1);
var y = Math.floor(Math.random() * ((6 - 1) + 1) + 1);
var dicetotal = x + y;
var double = 0;
$('.dice1').attr('id', "dice" + x);
$('.dice2').attr('id', "dice" + y);
if (x == y) { //<----checking if there is a double
var double = double++; //<---increment double count
//Now reroll the dice, but if you hit 3 doubles in a row, you get message go to jail.
}
};
I want to know if I am going to need some loop...Please help me. This is part of a monopoly game. What do i have to add in the code, to make it loop if there is a double.
我想知道我是否需要一些循环......请帮助我。这是垄断游戏的一部分。我必须在代码中添加什么才能使其循环（如果有双倍）。
采纳答案by LXSoft
You only need to make an recursive call:
您只需要进行递归调用：
var dbl = 0;
function rolldice() {
var x = Math.floor(Math.random() * ((6 - 1) + 1) + 1);
var y = Math.floor(Math.random() * ((6 - 1) + 1) + 1);
var dicetotal = x + y;
$('.dice1').attr('id', "dice" + x);
$('.dice2').attr('id', "dice" + y);
if (x == y) { //<----checking if there is a double
dbl++; //<---increment double count
if(dbl%3==0) $('.out').attr('id', "jail");
//Now reroll the dice, but if you hit 3 doubles in a row, you get message go to jail.
rolldice();
}
};
回答by MSzucs
I think you need to create something like this:
我认为你需要创建这样的东西：
var double = 0;
function rolldice(){
var x = Math.floor(Math.random() * ((6-1)+1) + 1);
var y = Math.floor(Math.random() * ((6-1)+1) + 1);
var dicetotal = x + y;
$('.dice1').attr('id', "dice" + x);
$('.dice2').attr('id', "dice" +y);
if(x==y) {
if (double < 3) {
double++; // increase dobule
rolldice(); // Call rolldice again...
} else {
// Here there is 3 in a row....
}
}
}
回答by Aashray
This has some complications. When there is a change of player, you need to reset the value of your variable for checking double rolls.
这有一些并发症。当玩家发生变化时，您需要重置变量的值以检查双掷。
Do the following:
请执行下列操作：
var dblRolls;
function userChange(){//call this on change of user
dblRolls=0;
rollDice();
}
function rolldice() {
var x = Math.floor(Math.random() * ((6 - 1) + 1) + 1);
var y = Math.floor(Math.random() * ((6 - 1) + 1) + 1);
var dicetotal = x + y;
var double = 0;
$('.dice1').attr('id', "dice" + x);
$('.dice2').attr('id', "dice" + y);
if (x == y) { //<----checking if there is a double
dblRoll++; //<---increment double count
if(dblRoll==3)
//jail
else
rollDice();
}
};
};
回答by Dan Iveson
Don't use a loop.
不要使用循环。
Instead add the doubles counter as a parameter for the rolldice()function and call the function from within itself:
而是将 doubles 计数器添加为rolldice()函数的参数并从其内部调用函数：
function rolldice(doubleCount) {
var x = Math.floor(Math.random() * ((6 - 1) + 1) + 1);
var y = Math.floor(Math.random() * ((6 - 1) + 1) + 1);
var dicetotal = x + y;
$('.dice1').attr('id', "dice" + x);
$('.dice2').attr('id', "dice" + y);
if (x == y) { //<----checking if there is a double
doubleCount++;
if (doubleCount == 3)
{
//go to jail
}
else
{
rolldice(doubleCount);
}
}
};
The initial call for a player's first roll would look like rolldice(0);
玩家第一次掷骰的初始呼叫看起来像 rolldice(0);
回答by user1781290
Ok, besides this is more than two hours old and has already 4 answers, I want to add my 2 cents.
好的，除了这已经超过两个小时并且已经有 4 个答案，我想加上我的 2 美分。
You state you want to make a Monopoly game. After most, if not all, dice rolls the player has to make decisions. That means after each roll you wait for user input (e.g., some button presses).
你说你想制作一个大富翁游戏。在大多数情况下，如果不是全部，玩家必须掷骰子做出决定。这意味着在每次滚动后，您都在等待用户输入（例如，按下某些按钮）。
All other answers postet suggest to use recursive calls in some way. Instead I suggest to store the number of doubles alongside with the current player in some global variable. You do not use a loop, but instead something like:
postet 的所有其他答案都建议以某种方式使用递归调用。相反，我建议将双打次数与当前玩家一起存储在某个全局变量中。您不使用循环，而是使用以下内容：
var doubleCount = 0;
function rolldice() {
var x = Math.floor(Math.random() * ((6 - 1) + 1) + 1);
var y = Math.floor(Math.random() * ((6 - 1) + 1) + 1);
var dicetotal = x + y;
$('.dice1').attr('id', "dice" + x);
$('.dice2').attr('id', "dice" + y);
if (x == y) { //<----checking if there is a double
doubleCount++; //<---increment double count
if (doubleCount > 2) {
// Got to Jail
}
}
// Proceed as usual and come back to this, when the user presses the "Roll" Button again
};
回答by Marcus Schack-Abildskov
This script works:
这个脚本有效：
function rollDice(){
var dice1 = document.getElementById("dice1");
var dice2 = document.getElementById("dice2");
var status = document.getElementById("status");
var d1 = Math.floor(Math.random() * 6) + 1;
var d2 = Math.floor(Math.random() * 6) + 1;
var diceTotal = d1 + d2;
dice1.innerHTML = d1;
dice2.innerHTML = d2;
status.innerHTML = "You rolled "+diceTotal+".";
if(d1 == d2){
status.innerHTML += "<br />DOUBLES! You get a free turn!!";
}
}
回答by Paul Schmitz
This is one possible solution.
这是一种可能的解决方案。
function rolldice(dbl=0){
var x = Math.floor(Math.random()*((6-1)+1) + 1);
var y = Math.floor(Math.random()*((6-1)+1) + 1);
if(x===y){
if(dbl!==3){
dbl++;
rolldice(dbl);
}else{
//goto jail
}
}else{
//no double
dbl=0;
}
}
or
或者
function rolldice(dbl=0){
var x = Math.floor(Math.random()*((6-1)+1) + 1);
var y = Math.floor(Math.random()*((6-1)+1) + 1);
if(x===y&&dbl!==3)
dbl++;
rolldice(dbl);
}else if(x===y&&dbl===3){
//goto jail
}else{
//no double
dbl=0;
}
}
