Bash - 如何将参数传递给通过标准输入读取的脚本
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Bash - How to pass arguments to a script that is read via standard input
提问by dabest1
I am trying execute a script from standard input and also pass arguments to it. Is there a way to do it?
我正在尝试从标准输入执行脚本并将参数传递给它。有没有办法做到这一点？
Let's say that I have the following:
假设我有以下几点：
cat script.sh | bash
How would I pass the arguments to the script?
我将如何将参数传递给脚本？
I do not want to do this:
我不想这样做：
bash script.sh arguments
Nor this:
也不是这个：
./script.sh arguments
回答by Michael Hoffman
On Linux,
在 Linux 上，
cat script.sh | bash /dev/stdin arguments
seems to work.
似乎工作。
回答by bryant1410
After @ccarton's comment:
cat script.sh | bash -s - arguments
It's more portable than @Michael Hoffman's solution.
它比@Michael Hoffman 的解决方案更便携。
