C++ 如何用数组初始化 glm::mat4？
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How to initialize a glm::mat4 with an array?
提问by j00hi
I'm using the OpenGL Mathematics Library (glm.g-truc.net) and want to initialize a glm::mat4with a float-array.
我正在使用 OpenGL 数学库 ( glm.g-truc.net) 并想glm::mat4用浮点数组初始化 a 。
float aaa[16];
glm::mat4 bbb(aaa);
This doesn't work.
这不起作用。
I guess the solution is trivial, but I don't know how to do it. I couldn't find a good documentation about glm. I would appreciate some helpful links.
我想解决方案很简单，但我不知道该怎么做。我找不到关于 glm 的好文档。我会很感激一些有用的链接。
回答by Matthew Marshall
Although there isn't a constructor, GLM includes make_* functions in glm/gtc/type_ptr.hpp:
虽然没有构造函数，但 GLM 在glm/gtc/type_ptr.hpp 中包含 make_* 函数：
#include <glm/gtc/type_ptr.hpp>
float aaa[16];
glm::mat4 bbb = glm::make_mat4(aaa);
回答by Anderson Silva
You can also directly copy the memory:
也可以直接复制内存：
float aaa[16] = {
1, 2, 3, 4,
5, 6, 7, 8,
9, 10, 11, 12,
13, 14, 15, 16
};
glm::mat4 bbb;
memcpy( glm::value_ptr( bbb ), aaa, sizeof( aaa ) );
回答by bdonlan
You could write an adapter function:
您可以编写一个适配器函数：
template<typename T>
tvec4<T> tvec4_from_t(const T *arr) {
return tvec4<T>(arr[0], arr[1], arr[2], arr[3]);
}
template<typename T>
tmat4<T> tmat4_from_t(const T *arr) {
return tmat4<T>(tvec4_from_t(arr), tvec4_from_t(arr + 4), tvec4_from_t(arr + 8), tvec4_from_t(arr + 12));
}
// later
float aaa[16];
glm::mat4 bbb = tmac4_from_t(aaa);
