Python TypeError: 'float' 对象不可调用是什么意思？
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TypeError: 'float' object is not callable what does it mean?
提问by Rosi .j
from random import uniform
def e(x):
n=len(x)
return(sum(x)/n)
def dmean(e,x,new):
n=len(x)
return((e*n+new)/(n+1))
l=[1,2,3,4,5,6,78]
e(l)
for i in range(0,5):
l.append(uniform(0,10))
e=e(l)
d=dmean(e,l,uniform(0,10))
回答by Craig
You have a function named e. The first time through the forloop, you overwrite the function name by creating a variable of the same name e=e(l). The next time through the loop, it tries to call the function, but eis now a floatvalue which can't be called. You can fix this by choosing a different name for your variable:
您有一个名为e. 第一次for循环时，您通过创建同名变量来覆盖函数名称e=e(l)。下一次循环时，它尝试调用该函数，但e现在是一个float无法调用的值。您可以通过为变量选择不同的名称来解决此问题：
for i in range(0,5):
l.append(uniform(0,10))
e_value=e(l)
d=dmean(e_value,l,uniform(0,10))
As you can see, Python doesn't distinguish between variable names and function names, so you have to make sure not to use the same name for a variable and a function.
如您所见，Python 不区分变量名和函数名，因此您必须确保不要对变量和函数使用相同的名称。
